The balanced chemical equation for the reaction between chlorine gas and sodium is: 2Na + Cl2 -> 2NaCl Using the equation, we can see that 1 mole of chlorine gas (Cl2) reacts with 2 moles of sodium (2Na). To calculate the mass of chlorine gas needed to react with 92 grams of sodium, first convert 92 grams of sodium to moles, then use the mole ratio from the balanced equation to find the moles of chlorine gas needed. Finally, convert the moles of chlorine gas to grams.
Sodium reacts with chlorine gas in a 1:1 molar ratio. Thus, for 2.00 mol of sodium, 2.00 mol of chlorine gas is required. The molar mass of chlorine gas is approximately 70.91 g/mol. Therefore, the mass of chlorine gas needed is 2.00 mol x 70.91 g/mol = 141.82 grams.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
14 percent sodium hypochlorite refers to the weight concentration of sodium hypochlorite in the solution. It does not refer to the concentration of chlorine gas, which would be different due to the molecular weight difference between sodium hypochlorite and chlorine gas.
The molar mass of sodium chloride is 58.44 g/mol. To find the mass of sodium chloride formed, you need to compare the moles of sodium and chlorine to determine the limiting reactant. Calculate moles of sodium and chlorine, determine limiting reactant, and use stoichiometry to find mass of sodium chloride formed.
The percentage of sodium in sodium chloride is 39,665 83 %. Mass of NaCl = Mass of sodium X 2,51
The sodium metal will react with chlorine gas to form sodium chloride. The reaction involves a single displacement reaction where sodium replaces chlorine in its diatomic form to form NaCl. The final mass of the flask will increase by 2.0 grams due to the formation of sodium chloride.
The balanced chemical equation for the reaction between chlorine gas and sodium is: 2Na + Cl2 -> 2NaCl Using the equation, we can see that 1 mole of chlorine gas (Cl2) reacts with 2 moles of sodium (2Na). To calculate the mass of chlorine gas needed to react with 92 grams of sodium, first convert 92 grams of sodium to moles, then use the mole ratio from the balanced equation to find the moles of chlorine gas needed. Finally, convert the moles of chlorine gas to grams.
The ratio mass of chlorine/mass of sodium is 1,5.
Sodium reacts with chlorine gas in a 1:1 molar ratio. Thus, for 2.00 mol of sodium, 2.00 mol of chlorine gas is required. The molar mass of chlorine gas is approximately 70.91 g/mol. Therefore, the mass of chlorine gas needed is 2.00 mol x 70.91 g/mol = 141.82 grams.
By atoms it is 50% sodium and 50% chlorine. By mass (sodium is 23.0, chlorine is 35.5, salt is 58.5) is 39.3% sodium and 60.7% chlorine.
To find the answer, we multiply the 7 grams of NaCl by the ratio of the molar mass of chlorine over the molar mass of sodium chloride. By doing this, we find that there are about 4.25 grams of chlorine in 7 grams of NaCl.
14 percent sodium hypochlorite refers to the weight concentration of sodium hypochlorite in the solution. It does not refer to the concentration of chlorine gas, which would be different due to the molecular weight difference between sodium hypochlorite and chlorine gas.
The equation for the reaction between sodium and chlorine is 2 Na + Cl2 -> 2 NaCl. This equation shows that equal numbers of formula units of sodium and chlorine are changed during the reaction. The gram Atomic Mass of two sodium atoms is 2 [exact] X 22.9898 or45.9796. therefore the specified amount of sodium is 92.0/45.9796 or 2.00 double gram atoms, to the justified number of significant digits. Therefore 2.00 double gram atoms of chlorine are required. The gram atomic mass of chlorine is 35.453, and four times this amount, or 142 grams of chlorine, to the justified number of significant digits, are needed for complete reaction.
The molar mass of sodium chloride is 58.44 g/mol. To find the mass of sodium chloride formed, you need to compare the moles of sodium and chlorine to determine the limiting reactant. Calculate moles of sodium and chlorine, determine limiting reactant, and use stoichiometry to find mass of sodium chloride formed.
50 g sodium chloride (NaCl) contain 30,167 g chlorine.
The balanced chemical equation for the reaction between sodium and chlorine gas is 2Na + Cl2 -> 2NaCl. From the equation, we see that 1 mole of chlorine gas reacts with 2 moles of sodium. First, calculate the moles of sodium in 92.0 g, then use the mole ratio to find the moles of chlorine gas needed, and finally convert to grams.