Two step process. First this formula finding period, which is Hertz. (s -1)( Z number lithium = 3 )
Hertz = (3.29 X 1015 s -1)*(Z2)*[1/Nf2 - 1/Ni2]
Hertz = (3.29 X 1015 s -1)*(32)*[1/22 - 1/42]
Hertz = (3.29 X 1015 s -1)*(9)*(1/4 - 1/16)
= 5.55 X 1015 Hertz
------------------------------now,
Wavelength = speed of light/Hertz
Wavelength = 2.998 X 108 (m/s)/5.55 X 1015 Hertz (s -1)
= 5.40 X 10 -8 meters
================== ( 54 nanometers ????? Seems unreasonable, but the formulas and work check )
The wavelength of light emitted during this transition can be calculated using the Rydberg formula: ( \frac{1}{\lambda} = R_H \left(\frac{1}{n_f^2} - \frac{1}{n_i^2}\right) ), where ( n_f = 2 ) and ( n_i = 4 ) for the given transition. Lithium has an atomic number of 3, so the Rydberg constant ( R_H = 1.097 \times 10^7 m^{-1} ). Substituting these values into the formula will give you the wavelength of light emitted.
An electron is transferred from the 2s orbital of a lithium atom to create a Li+ ion.
An electron is transferred from the 2s orbital to form Li+. This results in the removal of the outermost electron in the lithium atom, leading to the formation of a lithium ion.
An electron from the 2s orbital in a lithium atom is transferred to form a Li ion. This results in the lithium atom losing one electron, leading to the formation of a positively charged Li ion.
The orbital diagram for lithium (Li) would show two electrons occupying the 1s orbital and one electron in the 2s orbital. This corresponds to the electron configuration of 1s^2 2s^1 for lithium.
Lithium donates an electron to fluorine, forming lithium cations and fluorine anions that attract each other via ionic bonds. This results in the formation of lithium fluoride, a stable compound that satisfies the octet rule for both lithium and fluorine.
The actual transition of the electron from a higher energy orbital to a lower energy orbital happens almost instantaneously, typically on the order of femtoseconds (10^-15 seconds). This rapid transition results in the emission of light as photons are released.
In lithium, the orbital of highest relative energy is the 2s orbital. This is due to the fact that, in the electron configuration of lithium (1s^2 2s^1), the 2s orbital is farther from the nucleus compared to the 1s orbital, resulting in higher energy.
f-f transition: the transition of an electron from an f orbital which is lower in energy to an f orbital which is higher in energy is a f-f transition.
An electron is transferred from the 2s orbital of a lithium atom to create a Li+ ion.
An electron is transferred from the 2s orbital to form Li+. This results in the removal of the outermost electron in the lithium atom, leading to the formation of a lithium ion.
The electron configuration for lithium is 1s^2 2s^1. This means that lithium has 3 electrons, with two in the 1s orbital and one in the 2s orbital.
The complete electron configuration of lithium is 1s^2 2s^1. This means that lithium has 3 electrons, with 2 electrons in the 1s orbital and 1 electron in the 2s orbital.
An electron is transferred from the 2s orbital of lithium to form a Li ion. This results in the formation of a Li+ ion with a filled 1s and empty 2s orbital.
ok so you'll notice that lithium is on the second row of the periodic table, this means that its the next orbital hydrogen = 1s1 orbital helium = 2s1 orbital lithium = 2s1, 1s2 orbital removing the outter electron from lithium means that lithium has lost a minus charge and therefore must have a plus charge, this is called a cation. removing the electron also means now that there are no electrons in the s2 level do lithium is left with a 2s1 orbital, this is a very stable configuration and lithium wont loose any more electrons so your lithium ion will be nucleus with 3 protons 4 neutrons and 2 electrons with a plus charge to represent the loss of an electron
The transition metal element with only one electron in its 5s orbital is copper (Cu).
Typical transition elements are those elements in which d orbital is in the process of completion.d orbital can occupy 10 electrons. if in any element d orbital contain less than 10 electron it means it has incomplete d orbital and d orbital is in the process of completion. for example Sc has electronic configuration 3d1 4s2. it has 1 e in d orbital. so Sc is typical transition elements.
An electron from the 2s orbital in a lithium atom is transferred to form a Li ion. This results in the lithium atom losing one electron, leading to the formation of a positively charged Li ion.