56g N2= 4 moles 25 c = 298.15 J=K 750mmHG= .987 atm r=.08206 v=(nRT)/P v= (4*.08206*298.15)/.987 v= 99.2 l r= a constant.
To find the volume of a gas, we can use the ideal gas law: PV = nRT. First, calculate the moles of nitrogen using the given mass and molar mass. Then, rearrange the ideal gas law to solve for volume: V = nRT/P. Plug in the values for n (moles), R (ideal gas constant), T (temperature in Kelvin), and P (pressure) to find the volume.
The significant figures for 56g are two, as there are two non-zero digits in the number.
To find the mass of oxygen containing the same number of molecules as 42g of nitrogen, we need to compare their molar masses. The molar mass of nitrogen is 28 g/mol and oxygen is 32 g/mol. Since the same number of molecules of each substance have the same number of atoms, we can calculate the mass of oxygen by setting up a proportion: (42g N) / (28 g/mol N) = (x g O) / (32 g/mol O) Solving for x, the mass of oxygen containing the same number of molecules as 42g of nitrogen is 56g.
Approximately 161 grams of lead nitrate will dissolve in 100mL of cold water at room temperature.
The amount of particles (any kind) in ONE mole (of any substance) is always equal to Avogadro's number: 6.02*10+23 (This is the definition of a 'Mole'. It is just a number like a 'dozen' -12- or 'gross' -144-, though much larger. There is nothing 'chemical' in this number, however) So, here is your answer: 0.56 mole = 0.56 * 6.02*10+23 = 3.37*10+23
To prepare 1 liter of 0.05N KOH solution, you would need to dissolve 2.8 grams of potassium hydroxide (KOH) in water and dilute to a final volume of 1 liter. Always remember to wear appropriate safety gear and handle chemicals with caution.
56g=0.56kg
Density = Mass/Volume = 0.622... grams per ml
Assuming the volume is in cubic cm and not cm(!), Density = Mass/Volume = 56g/28cm3 = 2 grams per cm3
130% of 56g = 130% * 56 = 1.3 * 56 = 72.8g
Density = Mass/Volume => V = M/D So Vol = 25.8/2.56 = 10.1 units (approx) of the volume in which the density was expressed.
The significant figures for 56g are two, as there are two non-zero digits in the number.
The energy required to melt a substance can be calculated using the formula: Energy = mass x heat of fusion. For water, the heat of fusion is 334 J/g. Therefore, the energy required to melt 56g of water would be 56g x 334 J/g = 18,704 J.
A standard tennis ball weighs about 56g-58g.
here is a code for membership mee 3d5 56g ht6 8ty
2 oz (That's 56g in grown-up measurement).
1 cup = 56 grams
a lollypop has 24 carbs in it