0
What is the valume of oxygen occupied by 2 moles at 1.3 ATM pressure and 300 k?
Wiki User
∙ 7y ago
The volume of a gas can be calculated using the ideal gas law equation, (PV = nRT), where (P) is pressure, (V) is volume, (n) is the number of moles, (R) is the ideal gas constant, and (T) is temperature. Rearranging the equation to solve for volume gives us: (V = \frac{{nRT}}{P}). Plugging in the values, we get: (V = \frac{{2\ moles \times 0.0821\ L \cdot atm/mol \cdot K \times 300\ K}}{1.3\ atm} = 37.85\ L).
Add your answer:
Earn +20 pts
What is the volume of oxygen occupied by two moles?
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
What volume will be occupied by 8.00 of oxygen?
At room temperature and pressure, 1 mole of ideal gas occupies 22.4 liters. Therefore, 8.00 moles of oxygen will occupy 8.00 x 22.4 = 179.2 liters.
A 300-milliliter container that is filled with 100 milliliters of oxygen and 200 milliliters of hydrogen has a total pressure of 750 millimeters of mercury What is the partial pressure of the oxygen?
The partial pressure of oxygen can be calculated using the partial pressure formula: P(O2) = (moles of O2 / total moles) x total pressure. First, convert milliliters of gases into moles using the ideal gas law. Then, apply the formula to find the partial pressure of oxygen.
What volume occupied by 1.50 moles of CH4 at STP is?
1 mole of gas at STP (Standard Temperature and Pressure) occupies 22.4 L. Therefore, 1.50 moles of CH4 at STP would occupy 33.6 L (1.50 moles x 22.4 L/mol).
How many moles of oxygen are in 3.7 moles of C8H11NO2?
Since there are 8 oxygen atoms in each molecule of C8H11NO2, you would have 29.6 moles of oxygen in 3.7 moles of C8H11NO2.
What is the volume of oxygen occupied by two moles?
The molar volume of a gas at STP (standard temperature and pressure) is 22.4 L/mol. Therefore, the volume occupied by 2 moles of oxygen would be 44.8 L.
What is the volume of oxygen occupied by 2 moles at 1.3 ATM pressure at 300 k?
38 L
What is the volume of oxygen occupied by 2 moles at 1.3 ATM pressure and 300 K Use PV nRT.?
38 L
What volume will be occupied by 8.00 of oxygen?
At room temperature and pressure, 1 mole of ideal gas occupies 22.4 liters. Therefore, 8.00 moles of oxygen will occupy 8.00 x 22.4 = 179.2 liters.
How many moles of oxygen gas are there in 135 liters of oxygen at Standard Temerature Pressure?
The equivalent in moles is 6,03.
A 300-milliliter container that is filled with 100 milliliters of oxygen and 200 milliliters of hydrogen has a total pressure of 750 millimeters of mercury What is the partial pressure of the oxygen?
The partial pressure of oxygen can be calculated using the partial pressure formula: P(O2) = (moles of O2 / total moles) x total pressure. First, convert milliliters of gases into moles using the ideal gas law. Then, apply the formula to find the partial pressure of oxygen.
What volume is occupied of 0.48 moles of hydrogen?
The volume of a gas depends on its pressure, temperature, and volume according to the ideal gas law PV = nRT. Without knowing the pressure, temperature, or container size, it's not possible to determine the volume occupied by the 0.48 moles of hydrogen.
When a container is filled with 3 moles of helium gas 2 moles of oxygen gas nd 1 mole of carbon dioxide gas the pressure in the container is 8787 kPa what is the partial pressure of the oxygen gas?
The partial pressure of oxygen is 128 kPa.
What volume occupied by 1.50 moles of CH4 at STP is?
1 mole of gas at STP (Standard Temperature and Pressure) occupies 22.4 L. Therefore, 1.50 moles of CH4 at STP would occupy 33.6 L (1.50 moles x 22.4 L/mol).
How many moles of nitrogen and oxygen are in a cubic foot?
To determine the number of moles of nitrogen and oxygen in a given volume like a cubic foot, you would first need to know the pressure and temperature of the gas. Then you can use the ideal gas law equation, PV = nRT, where P is pressure, V is volume, n is moles, R is the ideal gas constant, and T is temperature. So without knowing the pressure and temperature, it is not possible to determine the number of moles of nitrogen and oxygen in a cubic foot.
Calculate the number of moles of oxygen that will dissolve in 45 L of water at 20C if the partial pressure of oxygen is 0.21 ATM Henrys constant for oxygen is 0.0013 mol L ATM?
Using Henry's law, the number of moles of oxygen that will dissolve is calculated by multiplying Henry's constant by the partial pressure of oxygen and the volume of water. So, moles of oxygen = 0.0013 mol L ATM * 0.21 ATM * 45 L = 0.1233 mol of oxygen will dissolve in 45 L of water at 20C.
How many moles of oxygen are in 3.7 moles of C8H11NO2?
Since there are 8 oxygen atoms in each molecule of C8H11NO2, you would have 29.6 moles of oxygen in 3.7 moles of C8H11NO2.
