The usual oxidation number of oxygen is -2, while the usual oxidation number of hydrogen is +1.
The oxidation number for Mn in H2MnO3 is +3. In this compound, oxygen is typically assigned an oxidation number of -2, and hydrogen is +1. By considering the overall charge of the compound and assigning hydrogen and oxygen their usual oxidation states, the oxidation number of Mn can be calculated as +3.
The oxidation number of antimony in Sb2O5 is +5. Each oxygen atom has an oxidation number of -2, so the total contribution of oxygen is -10. Since the compound is neutral, the sum of oxidation numbers must be zero, leading to +5 for antimony.
To find the oxidation number of chlorine, consider that chlorine typically has an oxidation number of -1 in its compounds. However, in certain situations, such as when bonded with oxygen or other halogens, chlorine can have different oxidation states. It's important to follow the usual oxidation number rules and balance the charges in the compound to determine the oxidation number of chlorine.
In most compounds oxygen will have an oxidation state of -2. The only exceptions are peroxides (-1), superoxides (-1/2), and compounds in which oxygen bonds with fluorine (+1 or +2).
The usual oxidation number of oxygen is -2, while the usual oxidation number of hydrogen is +1.
The oxidation number for Mn in H2MnO3 is +3. In this compound, oxygen is typically assigned an oxidation number of -2, and hydrogen is +1. By considering the overall charge of the compound and assigning hydrogen and oxygen their usual oxidation states, the oxidation number of Mn can be calculated as +3.
The oxidation number of antimony in Sb2O5 is +5. Each oxygen atom has an oxidation number of -2, so the total contribution of oxygen is -10. Since the compound is neutral, the sum of oxidation numbers must be zero, leading to +5 for antimony.
To find the oxidation number of chlorine, consider that chlorine typically has an oxidation number of -1 in its compounds. However, in certain situations, such as when bonded with oxygen or other halogens, chlorine can have different oxidation states. It's important to follow the usual oxidation number rules and balance the charges in the compound to determine the oxidation number of chlorine.
In most compounds oxygen will have an oxidation state of -2. The only exceptions are peroxides (-1), superoxides (-1/2), and compounds in which oxygen bonds with fluorine (+1 or +2).
To determine the oxidation number of an element, consider its usual oxidation state based on its position in the periodic table and the known oxidation states of other elements in the compound. In a neutral compound, the sum of the oxidation numbers must equal zero, and in an ion, the sum must equal the charge of the ion. Use these rules to assign the oxidation number of the element.
An oxidation state is a number that is assigned to an element in a chemical combination.
The oxidation number of carbon in carbonate (CO3^2-) is +4. In the carbonate ion, each oxygen atom has an oxidation number of -2, so the overall charge of the ion is -2. This means the oxidation number of carbon must be +4 to balance the charges in the compound.
The oxidation number for C in NH2CONH2 is +2. This is because each hydrogen has an oxidation number of +1, and oxygen has an oxidation number of -2. By assigning hydrogen and oxygen their usual oxidation numbers, we can determine that the nitrogen atoms in NH2CONH2 have an oxidation state of -3, and since each nitrogen atom contributes three electrons to the carbon atom, the overall oxidation state of carbon is +2.
+1 for K -2 for each O +7 for I
This is the usual formula for elemental oxygen in its gaseous state. It could also be called a "diatomic oxygen molecule."
+1 for hydrogen in most of the compounds and -1 in hydrides and hydrocarbons