This is an exception to the octet rule, meaning you will have more than 8 electrons on the Xe in the center.
There are 12 electrons to be placed. 4 + 8 = 12. 4 comes from the hydrogens which each give one, and 8 from the Xe because it is in the 8A group.
They will be arranged so that all have a single bond to H and that leaves you with 4 electrons still to place to make 12. So they go on the Xe (two pairs).
H
H -Xe - H
H
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XeH4 has a square planar molecular geometry with the xenon atom at the center and hydrogen atoms at the corners of the square. The xenon atom forms four single covalent bonds with each of the four hydrogen atoms.
The Lewis dot structure for xenon tetrahydride (XeH4) consists of Xenon (Xe) at the center with four hydrogen (H) atoms bonded to it. Xenon has 8 valence electrons, so it shares one electron with each hydrogen to complete its octet. The structure forms a tetrahedral shape with Xenon as the central atom.
The hydride formula for xenon is XeH4. Xenon typically forms compounds with fluorine, oxygen, and nitrogen, but it can also form a hydride by bonding with hydrogen.
In the Lewis dot structure for XeH4, xenon (Xe) is surrounded by four hydrogen (H) atoms bonded to it. Xenon has two lone pairs of electrons on it. The overall structure is linear, with xenon as the central atom.
The formula of the hydride formed by xenon is XeH4. Xenon forms a stable hydride with a coordination number of 4 due to its large size and low electronegativity.
The IUPAC name of a compound with the structure "structure to IUPAC name converter" is not provided as it is not a valid chemical structure. Please provide a specific chemical structure for accurate naming.