The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
The pH of a solution with a H+ concentration of 7.0 x 10^-2 M can be calculated using the formula pH = -log[H+]. In this case, pH = -log(7.0 x 10^-2) = 1.15.
The pH of a solution with [H+] = 7.0 x 10^-2 M is pH = -log(7.0 x 10^-2) = 1.15.
The pH of a hydrogen solution with a concentration of 10^-2 M is 2. This is because the pH is calculated as the negative logarithm (base 10) of the hydrogen ion concentration.
There are 2.75 equivalents of Mg^2+ present in a solution that contains 2.75 mol of Mg^2+. This is because the number of equivalents is equal to the number of moles for ions with a +2 charge.
105/70 + 45/70 + 49/70 = 199/70 or 2 and 59/70
It is: (5+2)*10 = 70
The pH of a solution with [H+] = 7.0 x 10^-2 is pH = -log(7.0 x 10^-2) = 1.15.
1.15 (Apex)
An equation, solution x = -10
Without any equality signs the given terms can't be classed as equations.
the answer is y minus 10 divided by 2.
An equation, solution x = -10
1/10 + 2/7 = 7/70 + 20/70 = 27/70
2/5+3/10 equals 7/10 or 70%.
2 × ? × 5 = 70 → 2 × 5 × ? = 70 → 10 × ? = 70 → (10 ÷ 10) × ? = 70 ÷ 10 → ? = 7 → The blank is 7.
1.39