Phenol is converted to aniline via the Zinin reduction reaction, which involves the reaction of phenol with ammonia and sodium metal. The phenol first forms a sodium phenoxide intermediate, which reacts with ammonia to give an amine salt. Finally, the amine salt is then reduced by sodium metal to produce aniline.
Aniline has a higher boiling point than phenol because aniline can form strong hydrogen bonds due to the presence of an amino group. Phenol has a higher boiling point than toluene because phenol molecules can form intermolecular hydrogen bonds because of the hydroxyl group. Toluene has a higher boiling point than benzene due to the presence of a bulky methyl group which increases Van der Waals forces between toluene molecules.
The reaction of aniline with acetic anhydride typically forms the product N-phenylacetamide and acetic acid. The chemical equation for the reaction can be represented as: C6H5NH2 + (CH3CO)2O → C6H5NHC(O)CH3 + CH3COOH.
The formula is for benzyl acetate (as an example).
In the reaction between phenol and sodium hydroxide, the phenol is deprotonated by the base, forming the phenolate ion. This reaction is an acid-base reaction where phenol acts as an acid and donates a proton to form water. The products of the reaction are the phenolate ion and water.
Phenol reacts with potassium permanganate in an acidic medium to form benzoquinone as the main product, along with small amounts of hydroquinone. This reaction is a redox reaction where phenol is oxidized to form benzoquinone.
React aniline with HCl/NaNO2 (diazotisation) followed by reaction with KOH to give phenol. Nitration of phenol with fuming nitric acid gives picric acid (or trinitrophenol).
In the Leuckart-Wallach reaction, phenol is converted into aniline through the reduction of the nitro group, followed by acid hydrolysis.
In o-aniline phenol Intramolecular hydrogen bonding occurs which is not possible in meta and is responsible for less solubility
In the Reimer-Tiemann reaction, the electrophile is the carbene (CHCl3) that forms from the reaction of phenol with CCl4 in the presence of a base such as NaOH. This carbene then reacts with phenol to form the trichloromethane derivative. The mechanism involves the generation of the carbene intermediate, which attacks the phenol molecule to form the final product.
Aniline has a higher boiling point than phenol because aniline can form strong hydrogen bonds due to the presence of an amino group. Phenol has a higher boiling point than toluene because phenol molecules can form intermolecular hydrogen bonds because of the hydroxyl group. Toluene has a higher boiling point than benzene due to the presence of a bulky methyl group which increases Van der Waals forces between toluene molecules.
The product of a reaction between bromine and aniline in a non-polar solvent is typically the bromination of aniline, where bromine substitutes a hydrogen atom on the benzene ring of aniline to form bromoaniline. This reaction is an electrophilic aromatic substitution reaction.
The reaction of aniline with acetic anhydride typically forms the product N-phenylacetamide and acetic acid. The chemical equation for the reaction can be represented as: C6H5NH2 + (CH3CO)2O → C6H5NHC(O)CH3 + CH3COOH.
Phenol reacts with phosphorus pentachloride to form chlorobenzene and phosphoric acid as byproduct. The reaction involves substitution of the hydroxyl group in phenol with a chlorine atom.
The reaction product of bromine and phenol is 2,4,6-tribromophenol. In this reaction, the bromine replaces the hydrogen atoms on the phenol ring to form a tribrominated product.
The balanced chemical equation for the reaction of phenol (C6H5OH) with sodium carbonate (Na2CO3) is: 2C6H5OH + Na2CO3 → 2C6H5ONa + H2O + CO2
Benzoyl chloride reacts with aniline to form N-phenylbenzamide. In the reaction, the chlorine atom of benzoyl chloride is replaced by the amino group of aniline. The reaction is often carried out in the presence of a base to help neutralize the hydrogen chloride byproduct.
The formula is for benzyl acetate (as an example).