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expected configuration for Cr is

1s2 2s2 2p6 3s2 3p6 4s2 3d4

but in real, it is

1s2 2s2 2p6 3s2 3p6 4s1 3d5

electron from 4s orbital jumps to 3d orbital to get stable configuration.

so the last electron comes in 3d orbital as filling of 3d takes place after filling of 4s orbital.

Hence,quantum numbers for last electron in Cr is :-

n = 3

l = 2

m = +2

s = +1/2

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12y ago
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6mo ago

The last electron in cobalt has a quantum number of 3 for its principal quantum number (n), 4 for its azimuthal quantum number (l), -1 for its magnetic quantum number (m_l), and +1/2 for its spin quantum number (m_s).

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11y ago

n=3 l=2 m=-1 s =-1/2

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Q: What is the quantum number for the last electron in cobalt?
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