expected configuration for Cr is
1s2 2s2 2p6 3s2 3p6 4s2 3d4
but in real, it is
1s2 2s2 2p6 3s2 3p6 4s1 3d5
electron from 4s orbital jumps to 3d orbital to get stable configuration.
so the last electron comes in 3d orbital as filling of 3d takes place after filling of 4s orbital.
Hence,quantum numbers for last electron in Cr is :-
n = 3
l = 2
m = +2
s = +1/2
The last electron in gold is located in the 6s orbital. Therefore, the quantum numbers for this electron would be n=6 (principal quantum number), l=0 (azimuthal quantum number), ml=0 (magnetic quantum number), and ms=+1/2 (spin quantum number).
The last electron in a copper atom has the quantum numbers n=3, l=2, ml=0, and ms=+1/2. The quantum numbers represent the energy level (n), sublevel (l), orbital orientation (ml), and electron spin (ms) of the electron, respectively.
n=4 l=2 ml= -1 ms= +1/2
The principal energy level is represented by the main energy level number (n). The valence electrons are the electrons found in the outermost energy level of an atom, which corresponds to the highest principal energy level (n).
Na has one valence electron i.e. 1 electron in valence(last) shell.
The last electron in gold is located in the 6s orbital. Therefore, the quantum numbers for this electron would be n=6 (principal quantum number), l=0 (azimuthal quantum number), ml=0 (magnetic quantum number), and ms=+1/2 (spin quantum number).
The four quantum numbers for the last electron in a boron atom (B) are: Principal quantum number (n) = 2 Azimuthal quantum number (l) = 1 Magnetic quantum number (ml) = 0 Spin quantum number (ms) = +1/2
The last electron in a copper atom has the quantum numbers n=3, l=2, ml=0, and ms=+1/2. The quantum numbers represent the energy level (n), sublevel (l), orbital orientation (ml), and electron spin (ms) of the electron, respectively.
The first three quantum numbers (principle, angular momentum, magnetic) are all whole numbers. The last quantum number (spin) is either ½ or -½.
Quantum numbers are a set of 4 imaginary numbers which explain the position and spin of electrons in an atom it can not explain an atom as a whole Iodine has 53 electrons so there are 53 sets of quantum numbers for Iodine.The above is correct. Assuming you meant to ask for the quantum numbers for the last electron added to Iodine, that would be n=5, l=1, m=0, s=1/2.
The quantum number for uranium is 92, which corresponds to its atomic number on the periodic table. Each element is uniquely identified by its atomic number, which indicates the number of protons in its nucleus.
The magnetic quantum number, ml, runs from -l to +l (sorry this font is rubbish the letter l looks like a 1) where l is the azimuthal, angular momentum quantum number. The magnetic quantum number ml depends on the orbital angular momentum (azimuthal) quantum number, l, which in turn depends on the principal quantum number, n. The orbital angular momentum (azimuthal) quantum number, l, runs from 0 to (n-1) where n is the principal quantum number. l= 0 is an s orbital, l= 1 is a p subshell, l= 2 is a d subshell, l=3 is an f subshell. The magnetic quantum number, ml, runs from -l to +l (sorry this font is rubbish the letter l looks like a 1). ml "defines " the shape of the orbital and the number within the subshell. As an example for a d orbital (l=2), the values are -2, -1, 0, +1, +2, , so 5 d orbitals in total.
The magnetic quantum number (m) of chlorine is determined by the orientation of its electron within a magnetic field. It can have values ranging from -l to +l, where l is the principal quantum number. For the chlorine atom, the magnetic quantum number can take on values of -1, 0, or +1.
It can reveal the number of valence electrons in the last shell.
exact, whole number amount of energy needed to move an electron to a higher energy level
Cobalt
n=4 l=2 ml= -1 ms= +1/2