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The product of the reaction between NaOH and H2C2O4 is sodium oxalate (Na2C2O4) and water (H2O). This is a double displacement reaction where the sodium ion from NaOH replaces the hydrogen ion in oxalic acid (H2C2O4) to form the salt sodium oxalate.
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What is the equation for hydrated oxalic acid and sodium hydroxide?
The equation for the reaction between hydrated oxalic acid (H2C2O4·2H2O) and sodium hydroxide (NaOH) is: H2C2O4·2H2O + 2NaOH → Na2C2O4 + 4H2O
What type of reaction is NaOH with Oxalic acid?
The reaction between NaOH and oxalic acid is a neutralization reaction, resulting in the formation of sodium oxalate and water. Oxalic acid is a dicarboxylic acid that can react with a base like NaOH to form a salt and water.
What is the chemical equation when oxalic acid reacts with sodium carbonate?
H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l) H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l)
What is the product when Na2Cr2O7 reacts with NaOH?
When Na2Cr2O7 reacts with NaOH, the products formed are Na2CrO4 and water. Sodium chromate (Na2CrO4) is the main product of this reaction.
What is the product of reacting ether with NaOH and then HCL?
The product of reacting ether with NaOH followed by HCl is an alcohol. The initial reaction with NaOH would form an alkoxide ion, which is then protonated by HCl to give the alcohol as the final product.
How would you calculate the unknown concentration of OH given that the solutions reach an equivilance point with their volumes being that NaOH is 12ml and H2C2O4 x H2O is 10ml?
To calculate the unknown concentration of OH-, you would first determine the number of moles of NaOH using its concentration and volume. Then, using the stoichiometry of the balanced chemical equation between NaOH and H2C2O4·H2O, you can find the number of moles of H2C2O4·H2O. Finally, divide the moles of H2C2O4·H2O by the volume of H2C2O4·H2O to find its concentration.
What is the equation for hydrated oxalic acid and sodium hydroxide?
The equation for the reaction between hydrated oxalic acid (H2C2O4·2H2O) and sodium hydroxide (NaOH) is: H2C2O4·2H2O + 2NaOH → Na2C2O4 + 4H2O
What type of reaction is NaOH with Oxalic acid?
The reaction between NaOH and oxalic acid is a neutralization reaction, resulting in the formation of sodium oxalate and water. Oxalic acid is a dicarboxylic acid that can react with a base like NaOH to form a salt and water.
What is the chemical equation when oxalic acid reacts with sodium carbonate?
H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l) H2C2O4 (aq) + 2 NaOH (aq) --> Na2C2O4 (aq) + 2 H2O (l)
What is the name of the compound H2C2O4?
The name of the compound H2C2O4 is oxalic acid.
Is water a product?
In some reactions water is a reactant, but in others it is a product. Ex: HCl + NaOH --> NaCl + water (water is a product) Na + water --> NaOH + hydrogen gas (water is a reactant)
What is the product when Na2Cr2O7 reacts with NaOH?
When Na2Cr2O7 reacts with NaOH, the products formed are Na2CrO4 and water. Sodium chromate (Na2CrO4) is the main product of this reaction.
What is the product of reacting ether with NaOH and then HCL?
The product of reacting ether with NaOH followed by HCl is an alcohol. The initial reaction with NaOH would form an alkoxide ion, which is then protonated by HCl to give the alcohol as the final product.
Which substances are reactants and which are products in this equation NaOH HCI H2O?
In this equation, NaOH and HCl are the reactants, and H2O is the product. The reaction is between sodium hydroxide (NaOH) and hydrochloric acid (HCl) to form water (H2O) as a product.
What will be the product of the reaction of ethanol and NaOH and iodine?
The reaction of ethanol with NaOH and iodine will yield iodoethane (ethyl iodide) as the product. The alcohol group in ethanol will be replaced by the iodine atom in the presence of NaOH.
If the reactants of a reaction are HCI and NaOH what could be a product?
NaCl
What is the complete formula equation for H2C2O4 plus H2SO4?
The equation for the reaction between oxalic acid (H2C2O4) and sulfuric acid (H2SO4) is: H2C2O4 + H2SO4 → CO2 + H2O + SO2 + H2O
