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To determine the pH of a solution of potassium hydroxide (KOH), we need to calculate the concentration of hydroxide ions (OH-) first. Since KOH dissociates completely in water, the concentration of OH- ions will be equal to the concentration of KOH. Therefore, the concentration of OH- ions in a 0.04 M KOH solution is also 0.04 M. To find the pOH, we take the negative logarithm (base 10) of the hydroxide ion concentration: pOH = -log(0.04) ≈ 1.4. Finally, to find the pH, we subtract the pOH from 14 (the sum of pH and pOH in water at 25°C): pH = 14 - 1.4 ≈ 12.6.
The pH of a 0.04 M KOH solution can be calculated by using the formula pH = 14 - pOH. In this case, the pOH is equal to -log(KOH concentration), so pOH = -log(0.04) = 1.4. Therefore, pH = 14 - 1.4 = 12.6.
0.04 M KOH produces an OH- concentration of 0.04 M. Thus, the pOH is -log 0.04 = 1.4 and the pH will be 14 - 1.4 = 12.6
pH of 0.04M KOH
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What is the PH of a 1.0x10 to the negative fourth power M solution of KOH?
The pH of a 1.0x10^-4 M solution of KOH is approximately 10.4. This is because KOH is a strong base that dissociates completely in water to produce hydroxide ions, which results in a basic solution.
What is the pH of a 1 x 10-5 M KOH solution?
The pH of a 1 x 10^-5 M KOH solution would be approximately 9. For a strong base like KOH, the pH can be calculated by taking the negative logarithm of the concentration of hydroxide ions.
What is the pH of a 10-5 m of koh solution?
The pH of a 10^-5 M KOH solution would be around 9. For a given concentration of a strong base like KOH, the pH can be calculated using the formula pH = 14 - pOH. Given that pOH = -log[OH-] and [OH-] = 10^-5 M in this case, pOH = 5. Therefore, pH = 14 - 5 = 9.
What is the pH of 3.0 M KOH?
The pH of a 3.0 M solution of KOH (potassium hydroxide) would be very high, around 13-14. This is because KOH is a strong base that completely dissociates in solution to release hydroxide ions, which results in a high concentration of hydroxide ions and a high pH.
What is the molarity of a solution with 0.2 moles of KOH in 100 mL of water?
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
What is the PH of a 1.0x10 to the negative fourth power M solution of KOH?
The pH of a 1.0x10^-4 M solution of KOH is approximately 10.4. This is because KOH is a strong base that dissociates completely in water to produce hydroxide ions, which results in a basic solution.
What is the pH of a 1 x 10-5 M KOH solution?
The pH of a 1 x 10^-5 M KOH solution would be approximately 9. For a strong base like KOH, the pH can be calculated by taking the negative logarithm of the concentration of hydroxide ions.
What is the pH of a 10-5 m of koh solution?
The pH of a 10^-5 M KOH solution would be around 9. For a given concentration of a strong base like KOH, the pH can be calculated using the formula pH = 14 - pOH. Given that pOH = -log[OH-] and [OH-] = 10^-5 M in this case, pOH = 5. Therefore, pH = 14 - 5 = 9.
What is the pH of 3.5 x 10 -4 M solution of KOH?
-log(3.5 X 10^-4 M) = 3.4559 14 - 3.4559 = 10.5 pH
What is the pH of 3.0 M KOH?
The pH of a 3.0 M solution of KOH (potassium hydroxide) would be very high, around 13-14. This is because KOH is a strong base that completely dissociates in solution to release hydroxide ions, which results in a high concentration of hydroxide ions and a high pH.
What is the pH of 0.067 0 M KOH solution?
The pH of a 0.0670 M KOH solution can be calculated using the formula pH = 14 - pOH. Since KOH dissociates completely in water to produce OH- ions, the pOH can be found by taking the negative logarithm of the hydroxide ion concentration (0.0670 M in this case). Then, pH = 14 - pOH, allowing you to determine the solution's pH.
What is the molarity of a solution with 0.2 moles of KOH in 100 mL of water?
Molarity = moles of solute/Liters of solution get moles KOH 6.31 grams KOH (1 mole KOH/56.108 grams) = 0.11246 moles KOH 0.250 M KOH = 0.11246 moles KOH/XL 0.11246/0.250 = 0.4498 liters = 450 milliliters
How many moles of KOH are contained in 750. mL of 5.00 M KOH solution?
To determine the number of moles of KOH in the solution, you can use the formula: moles = molarity x volume (L) First, convert the volume from mL to liters by dividing 750 mL by 1000. Then, multiply the molarity (5.00 M) by the volume in liters to find the number of moles of KOH in the solution.
A 30.0 ml sample of 0.200 m koh is titrated with 0.150 m hclo4 solution calculate the pH after 39.9 ml of hclo4 is added?
To solve this problem, you first need to determine the moles of KOH present in the 30.0 mL sample. Then calculate the moles of HClO4 added after 39.9 mL. Based on these concentrations, determine the excess and limiting reagents to find the resulting pH. Consider the reaction that occurs between KOH and HClO4, and use the stoichiometry to calculate the amount of products formed. Finally, calculate the pH using the concentration of the resulting solution.
What is the pH of a 1.0 10-3 M KOH solution?
[OH-] = 1x10^-3 M[H+][OH-] = 1x10^-14[H+] = 1x10^-14/1x10^-3 = 1x10^-11pH = -log 1x10^-11 = 11Done another way:pOH = -log [OH-] = -log 1x10^-3 = 3pH + pOH = 14pH = 14 - 3 = 11
A 25 ml sample of 723 m hclo4 is titrated with a 273 m koh solution the h3o concentration after 66.2 ml of koh is?
The balanced chemical equation for the reaction between HClO4 and KOH is HClO4 + KOH → KClO4 + H2O. By using the stoichiometry of the reaction, you can calculate the moles of HClO4 reacted with KOH. Then, use the remaining volume of KOH solution added to calculate the final H3O+ concentration in the solution.
you have 500 ml of a 1.5 m hcl solution (acid). if there is 250 ml of koh solution present (base). what will be the molarity of the koh (base)?
To find the molarity of the KOH solution, we need to know the concentration of the KOH solution in moles per liter. Without this information, we cannot calculate the molarity.
