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Supposed the acid and base are both strong:

pH of the acid is 0.0 and the pH of the base (hydroxide) is 14.0

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13y ago
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6mo ago

The pH of 0.1 M NaOH is approximately 13, as NaOH is a strong base that fully dissociates in water to produce hydroxide ions. The pH of 0.05 M NaOH would also be approximately 13, as the concentration of the base does not impact the basicity significantly when dealing with strong bases.

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11y ago

For 0.1 m NaOH, pOH = -log[OH-] = -log(0.1) = 1

pH + pOH = 14, So pH = 13

Same way for 0.05 m NaOH, pOH = -log(0.05) = 1.3

pH = 14 - 1.3 = 12.7

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10y ago

pH=0

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Q: What is the pH of 0.1m NaOH and 0.05m NaOH?
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