This should be SO4-2 ion. sulfur shows +6 in this ion.
In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
+6: Oxygen in oxyanions is assumed to have an oxidation state of -2; there are four such oxygen atoms, for a total of -8, and the SO4 anion has a charge of -2. This means that the sulfur atom must have an oxidation state of +6, because +6 added to - 8 = -2.
The oxidation state of an individual sulfur atom in SO4 is +6. In the sulfate ion (SO4^2-), each oxygen atom has an oxidation state of -2, for a total of -8. Since the overall charge of the sulfate ion is -2, the sulfur atom must have an oxidation state of +6 to balance out the charge.
This should be SO4-2 ion. sulfur shows +6 in this ion.
In (NH4)2Ce(SO4)3, the oxidation number of Ce is +3. The oxidation number of ammonium (NH4) is +1, and the oxidation number of sulfate (SO4) is -2.
The oxidation number of sulfur in H2SO4 is +6. This is because hydrogen has an oxidation number of +1 and oxygen has an oxidation number of -2, so by the rules of oxidation numbers, sulfur must have an oxidation number of +6 to balance the equation.
+6: Oxygen in oxyanions is assumed to have an oxidation state of -2; there are four such oxygen atoms, for a total of -8, and the SO4 anion has a charge of -2. This means that the sulfur atom must have an oxidation state of +6, because +6 added to - 8 = -2.
The oxidation state of an individual sulfur atom in SO4 is +6. In the sulfate ion (SO4^2-), each oxygen atom has an oxidation state of -2, for a total of -8. Since the overall charge of the sulfate ion is -2, the sulfur atom must have an oxidation state of +6 to balance out the charge.
The oxidation number of oxygen (O) in SO4 (sulfate) is -2. Since there are four oxygen atoms in the sulfate ion (SO4), they collectively contribute -8 to the overall charge of the ion, which is -2.
In ZnSO4, the oxidation state of Zn (Zinc) is +2, the oxidation state of sulfur (S) is +6, and the oxidation state of oxygen (O) is -2. This is because the overall charge of the compound is zero, so the sum of the oxidation states must equal zero.
The oxidation state of sulfur in SO4^2- is +6. This is because oxygen typically has an oxidation state of -2, and there are 4 oxygen atoms in SO4^2-. Since the overall charge of the ion is -2, the oxidation state of sulfur must be +6 to balance the charges.
The oxidation number of chromium (Cr) in Cr2(SO4)3 is +3. This is because the overall charge of the sulfate ion (SO4) is -2, and there are a total of 3 sulfate ions present in the compound, requiring the chromium to have an oxidation state of +3 to balance the charges.
SO4^2- has a net negative 2 charge.each O = 2-S = 6+
The oxidation number of calcium (Ca) is +2. The overall charge of a sulfate ion (SO4) is -2. Therefore, in CaSO4, calcium has an oxidation number of +2 and sulfate has an oxidation number of -2.
In this ion the oxidation state of sulfur is 6+ and the oxidation state of each oxygen is 2-