In oxygen containing anions that also include a less electronegative element, oxygen is taken to have an oxidation number of -2. A sulfate ion has a charge of -2. The four oxygen atoms of a sulfate ion have a total charge of 4 X -2 or -8; therefore, the oxygen atom must have an oxidation number of +6 to yield the correct value for the charge of the sulfate ions.
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
The oxidation number of sulfur in aluminum sulfate is +6. This is because each oxygen atom has an oxidation number of -2, and there are four oxygen atoms in the sulfate ion (SO4). The overall charge of the sulfate ion is -2, so the oxidation number of sulfur must be +6 to balance the charge.
There is no oxidation number for compounds, only the elements within compounds. The charge of SO4 (sulfate) is 2-. The oxidation number of each oxygen is 2-. The oxidation number of the sulfur in this compound is 6+.
The oxidation number of the polyatomic ion sulfate (SO4) is -2. Each oxygen atom contributes -2, and since sulfate has a charge of -2, the single sulfur atom must have an oxidation number of +6 to balance the charges.
For CaSO4 (calcium sulfate), the oxidation number of sulfur is +6. For SO4 (sulfate ion), the oxidation number of sulfur is +6. For SO2 (sulfur dioxide), the oxidation number of sulfur is +4. For SO3 (sulfur trioxide), the oxidation number of sulfur is +6.
Sulphur has 6 valence electrons. So its maximum oxidation number is +6.
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
The oxidation number of sulfur in aluminum sulfate is +6. This is because each oxygen atom has an oxidation number of -2, and there are four oxygen atoms in the sulfate ion (SO4). The overall charge of the sulfate ion is -2, so the oxidation number of sulfur must be +6 to balance the charge.
There is no oxidation number for compounds, only the elements within compounds. The charge of SO4 (sulfate) is 2-. The oxidation number of each oxygen is 2-. The oxidation number of the sulfur in this compound is 6+.
The oxidation number of the polyatomic ion sulfate (SO4) is -2. Each oxygen atom contributes -2, and since sulfate has a charge of -2, the single sulfur atom must have an oxidation number of +6 to balance the charges.
The oxidation number of sulphur in H2S is 2.
In an iodometric titration experiment, the oxidation number of sulfur changes from -2 in the thiosulfate ion (S2O32-) to +4 in the sulfate ion (SO42-) as sulfur gains oxygen atoms. This change indicates the transfer of electrons and oxidation of sulfur during the reaction.
The oxidation number for sulfur (S) in tin(IV) sulfate (Sn(SO4)2) is +6. This is because the overall charge of the sulfate ion (SO4) is -2, and there are two sulfate ions present in the compound, leading to a total charge of -4. The oxidation number of tin (Sn) in this compound is +4.
Things are complicated if we use the term valency. It is better to use the term Oxidation state or Oxidation Number. In SO2, the oxidation state of sulphur is +4 and In SO3, the oxidation state of sulphur is +6.
Oxygen atoms are generally considered to have an oxidation number of -2 in all oxyanions such as sulfate.
The oxidation number in atomic sulfur is 0. The oxidation number of sulfide ion is -2. With oxygen and other non metals, it makes numerous ions where its oxidation number varies from -2 to +6.