The oxidation number of nitrogen in N2F4 is +3. This is because the overall charge of the compound is 0, and since there are two nitrogen atoms each with an oxidation number of +3, the total contribution from nitrogen is +6, which is balanced by the -4 charge from four fluorine atoms.
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The minimum oxidation number for nitrogen is -3.
The oxidation number of nitrogen in ammonium nitrite (NH4NO2) is +3. In the ammonium ion (NH4+), nitrogen has an oxidation number of -3 and in the nitrite ion (NO2-), nitrogen has an oxidation number of +3.
The oxidation number of nitrogen in N2 is 0 since it is in its elemental form where the oxidation number is always 0.
The oxidation number of hydrogen in NH3 is +1, and the oxidation number of nitrogen is -3. This is because hydrogen typically has an oxidation number of +1 and in compounds, nitrogen usually has an oxidation number of -3.
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.