The oxidation number of Se in Se8 is 0. In elemental form, such as Se8, each atom has an oxidation number of 0.
The oxidation number of Br2 is 0. Each bromine atom in the Br2 molecule has an oxidation number of 0 because the molecule is in its elemental form.
The oxidation number change for the iron atom in a reaction is from Fe^0 (elemental form) to Fe^2+ or Fe^3+ (ionic form). This represents an oxidation of the iron atom, as it loses electrons and increases its oxidation state.
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
The oxidation number of a carbon atom in graphite is zero. Carbon in its elemental form has an oxidation number of zero because it is a nonmetal that is not bonded to more electronegative atoms.
0 in the elemental form, +3 in its compounds
0 in elemental form, +2 in its compounds
The oxidation number of Se in Se8 is 0. In elemental form, such as Se8, each atom has an oxidation number of 0.
The oxidation number of Br2 is 0. Each bromine atom in the Br2 molecule has an oxidation number of 0 because the molecule is in its elemental form.
oxidation number
The oxidation number change for the iron atom in a reaction is from Fe^0 (elemental form) to Fe^2+ or Fe^3+ (ionic form). This represents an oxidation of the iron atom, as it loses electrons and increases its oxidation state.
The oxidation number of sulfur in sulfur powder (S8) is 0. Each sulfur atom in the elemental form has an oxidation number of 0.
The oxidation number of a carbon atom in graphite is zero. Carbon in its elemental form has an oxidation number of zero because it is a nonmetal that is not bonded to more electronegative atoms.
The oxidation number of an atom with 12 protons is +2. This is because the number of protons in an atom determines its atomic number, which also corresponds to its charge in simple cationic compounds.
The oxidation number of an atom in its elemental form is always 0. Therefore, the oxidation number of F2 (fluorine gas) is 0.
The oxidation number of N in N2 is 0 since it is in its elemental form. In a diatomic molecule like N2, each nitrogen atom has an oxidation number of 0.
The oxidation number of S in S8 is 0. Each sulfur atom in S8 has an oxidation number of 0 because it is in its elemental form and not bonded to any other element.