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6mo ago

The oxidation number of N in (N2H5)2SO4 is -1. This is because the overall charge of the compound is neutral, and the oxidation number of S is +6. By using the oxidation numbers of S and O, we can determine that the oxidation number of N must be -1 to balance the charges in the compound.

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Q: What is the oxidation number of N in (N2H5)2SO4?
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