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If you mean MoO4 the oxidation number of Mo is 8 and the compound would be called Mo(VIII) oxide. This compound does not exist, it is theoretical- teachers and examiners often use such nonexistent compounds as teaching aids- why I don't know- i think it is misleading as there are plenty of real compounds about.
The oxidation number of Mo in MO4 is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms bonded to molybdenum in the MO4 molecule, resulting in a total charge of -8. To balance the overall charge of the molecule, the molybdenum must have an oxidation number of +6.
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What is the oxidation number for MO?
The oxidation number for the compound MO can vary depending on M. In general, oxygen has an oxidation number of -2. Therefore, you would need to know what element M represents in order to determine the oxidation number for MO.
What is the oxidation number of NaMoO3?
In NaMoO3, sodium (Na) has an oxidation number of +1, oxygen (O) has an oxidation number of -2, and the overall charge of the compound is 0. Since there is only one Mo atom in the compound, the oxidation number of molybdenum (Mo) can be calculated to be +6 using the formula: (+1) + x + 3(-2) = 0 where x is the oxidation number of Mo.
What is the oxidation number of Mo in MoO4 -2?
The oxidation number of oxygen is typically -2, so for the whole MoO4^2- ion (which has a charge of -2), the total oxidation number must sum up to -2. This means that the oxidation number of molybdenum (Mo) in MoO4^2- would be +6.
What is the oxidation number Mo in MoO4-2?
The oxidation number of oxygen is typically -2. Since there are four oxygen atoms in MoO4-2 and the overall charge is -2, the oxidation number of molybdenum (Mo) is calculated to be +6 to balance the negative charge.
What is the oxidation number of Mo in MoO42?
The oxidation number of molybdenum (Mo) in MoO4^2- is +6. This is because each oxygen atom has an oxidation number of -2, and since the overall charge of the ion is 2-, the oxidation number of Mo must be +6 to balance the charges.
What is the oxidation number for MO?
The oxidation number for the compound MO can vary depending on M. In general, oxygen has an oxidation number of -2. Therefore, you would need to know what element M represents in order to determine the oxidation number for MO.
What is the oxidation number of NaMoO3?
In NaMoO3, sodium (Na) has an oxidation number of +1, oxygen (O) has an oxidation number of -2, and the overall charge of the compound is 0. Since there is only one Mo atom in the compound, the oxidation number of molybdenum (Mo) can be calculated to be +6 using the formula: (+1) + x + 3(-2) = 0 where x is the oxidation number of Mo.
What is the oxidation number of Mo in MoO4 -2?
The oxidation number of oxygen is typically -2, so for the whole MoO4^2- ion (which has a charge of -2), the total oxidation number must sum up to -2. This means that the oxidation number of molybdenum (Mo) in MoO4^2- would be +6.
What is the oxidation number Mo in MoO4-2?
The oxidation number of oxygen is typically -2. Since there are four oxygen atoms in MoO4-2 and the overall charge is -2, the oxidation number of molybdenum (Mo) is calculated to be +6 to balance the negative charge.
What is the oxidation number of Mo in MoO42?
The oxidation number of molybdenum (Mo) in MoO4^2- is +6. This is because each oxygen atom has an oxidation number of -2, and since the overall charge of the ion is 2-, the oxidation number of Mo must be +6 to balance the charges.
What is the oxidation number of Mo in MoO4?
The oxidation number of molybdenum (Mo) in MoO4^2- is +6. This is because the overall charge of the compound is -2, and each oxygen atom has an oxidation number of -2. By setting up an equation (x + 4(-2) = -2), we find that x = +6.
What is the oxidation number of MoO4?
The oxidation number of molybdenum (Mo) in the MoO4^2- ion is +6. This is because oxygen typically has an oxidation number of -2, and there are four oxygen atoms in the persulfate ion (O4^2-), making the total charge -8. For the overall ion to have a charge of -2, molybdenum must have an oxidation number of +6 to balance the charges.
What is the oxidation number of molybdenumdisulfide?
MoS2. -2 for each S, +4 for Mo
What is the oxidation number of molybdenum disulphide?
In molybdenum disulfide (MoS2), molybdenum typically has an oxidation state of +4, and sulfur has an oxidation state of -2. Each Mo atom contributes a +4 oxidation state, while each S atom contributes a -2 oxidation state, which balances the overall charge of the compound.
What is the oxidation number of molybdenum?
MoS2. -2 for each S, +4 for Mo
What is the oxidation of Mo in MoO4?
The oxidation state of Mo in MoO4 is +6. This is because each oxygen atom has an oxidation state of -2, and since there are four oxygen atoms in the compound, the total oxidation state contributed by oxygen is -8. In order to balance the charge of the compound, the oxidation state of Mo must be +6.
What is the oxidation number for each sulfur atoms?
The oxidation number for the sulfur atom in compounds can vary depending on the specific compound. However, in most cases, the common oxidation number for sulfur is -2, as it tends to gain two electrons to achieve a stable electron configuration.
