The oxidation number of K (Potassium) in KBr (Potassium Bromide) is +1. This is because alkali metals like Potassium typically have an oxidation number of +1 in compounds.
The oxidation number of bromine in KBr is -1. In ionic compounds, the oxidation number of the cation (K+) is always equal to its charge, which is +1. Therefore, the oxidation number of bromine must be -1 to balance the overall charge of the compound.
To find the number of moles of KBr in the solution, first calculate the number of moles of KBr in the 25 mL solution using the given concentration and volume. $$moles = concentration \times volume$$ Then, multiply the moles by the molecular weight of KBr to get the mass of KBr in the solution if needed.
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of K (Potassium) in KBr (Potassium Bromide) is +1. This is because alkali metals like Potassium typically have an oxidation number of +1 in compounds.
The oxidation number of bromine in KBr is -1. In ionic compounds, the oxidation number of the cation (K+) is always equal to its charge, which is +1. Therefore, the oxidation number of bromine must be -1 to balance the overall charge of the compound.
To find the number of moles of KBr in the solution, first calculate the number of moles of KBr in the 25 mL solution using the given concentration and volume. $$moles = concentration \times volume$$ Then, multiply the moles by the molecular weight of KBr to get the mass of KBr in the solution if needed.
To find the number of moles in 22.23 g of KBr, we need to divide the given mass by the molar mass of KBr. The molar mass of KBr is 119 g/mol. Therefore, 22.23 g of KBr is equal to 0.187 moles.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.
The oxidation number for Nb in NbO2 is +4. Oxygen has an oxidation number of -2, so the overall charge of the compound must be balanced by the oxidation number of niobium.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7
The oxidation number for H is +1, and the oxidation number for O is -1.