Oxygen has -2,hydrogen has +1 and carbon has -1.But carbon do not have -1 state
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The oxidation number of carbon in C2H4O is +2, as each hydrogen has an oxidation number of +1 and each oxygen has an oxidation number of -2. By setting up the equation 2x + 4(+1) + 1(-2) = 0, you can solve for x to find the oxidation number of carbon.
C2H4O oxidation number is -1
2x+1(4)+1(-2)=0
2x+4-2=0
2x+2=0
2x=-2
x=-2/2
x=-1
The oxidation state of carbon in ethanal (C2H4O) is +2, as it is bonded to two more electronegative oxygens. The oxidation state of oxygen is -2, while the hydrogen atoms have an oxidation state of +1.
The formula that represents an aldehyde is c) C2H4O. Aldehydes have the general formula RCHO, where R is an alkyl or aryl group.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
The oxidation number of nitrosyl (NO) is +1. Nitrogen typically has an oxidation number of -3, and oxygen typically has an oxidation number of -2. In NO, nitrogen has a -3 oxidation number and oxygen has a -2 oxidation number, leading to an overall oxidation number of +1 for the nitrosyl ion.