LiBrO3 this decomposes to Li^(+) & BrO3^(-)
The bromate anion has a charge of '-1'
Use the standard for oxygen at '-2'
Since there are 3 oxygens then the oxygen moiety is 3 X -2 = -6
Creating a little sum
Br + -6( oxygen moiety) = -1( anion charge)
Br - 6 = -1
Add '6 'to both sides
Br = (+)5 The oxidation state of bromine.
The symbol for lithium bromate is LiBrO3.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
If Br had an oxidation number of +7, the net charge on the ion would be +1, and not -1. Thus, the oxidation number for Br in BrO3- should be 5+.
The oxidation number of Br in ZnBr2 is -1. In ZnBr2, zinc (Zn) has an oxidation number of +2, so the two bromine (Br) atoms each have an oxidation number of -1 to balance the charge of the compound.
The oxidation number of Br in BrO3 is +5. This is because the oxidation number of oxygen is usually -2, and since there are three oxygen atoms in BrO3, the total negative charge from oxygen is -6. To balance the charge of the compound which is neutral, the oxidation number of Br is therefore +5.
The symbol for lithium bromate is LiBrO3.
The oxidation number of Li in LiBr is +1, and the oxidation number of Br is -1.
If Br had an oxidation number of +7, the net charge on the ion would be +1, and not -1. Thus, the oxidation number for Br in BrO3- should be 5+.
The oxidation number of Br in ZnBr2 is -1. In ZnBr2, zinc (Zn) has an oxidation number of +2, so the two bromine (Br) atoms each have an oxidation number of -1 to balance the charge of the compound.
The oxidation number of Br in BrO3 is +5. This is because the oxidation number of oxygen is usually -2, and since there are three oxygen atoms in BrO3, the total negative charge from oxygen is -6. To balance the charge of the compound which is neutral, the oxidation number of Br is therefore +5.
The oxidation number of Br in KBrO3 is +5. This is because oxygen typically has an oxidation number of -2 and the overall compound has a neutral charge. Since there is only one Br atom in KBrO3 and the oxidation numbers of K and O are known, the oxidation number of Br can be calculated as +5 to balance the overall charge.
-2 for each O, +5 for Br
In KBr, potassium (K) has an oxidation number of +1, as it is a group 1 element. Bromine (Br) has an oxidation number of -1, since it is a halogen.
+1 for Na -1 for Br
The oxidation number of Br- is -1. Bromine typically has an oxidation state of -1 when it forms an ion by gaining one electron.
The oxidation number of Cs (Cesium) is +1, and the oxidation number of Br (Bromine) is -1. In CsBr, Cesium donates one electron to Bromine, resulting in Cs having an oxidation number of +1 and Br having an oxidation number of -1 in the compound.
The oxidation number of Br in BrO is +1. This is because oxygen is typically assigned an oxidation number of -2, and the overall charge of the compound is 0 since there are no additional elements present. Therefore, the oxidation number of Br must be +1 in order to balance the charges.