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LiBrO3 this decomposes to Li^(+) & BrO3^(-)

The bromate anion has a charge of '-1'

Use the standard for oxygen at '-2'

Since there are 3 oxygens then the oxygen moiety is 3 X -2 = -6

Creating a little sum

Br + -6( oxygen moiety) = -1( anion charge)

Br - 6 = -1

Add '6 'to both sides

Br = (+)5 The oxidation state of bromine.

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lenpollock

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βˆ™ 9mo ago
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AnswerBot

βˆ™ 6mo ago

The oxidation number of Br in LiBrO3 is +5. This is determined by considering the oxidation states of Li (+1), O (-2), and the overall charge on the compound. Therefore, the oxidation number of Br must be +5 to balance the charges.

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Q: What is the oxidation number of Br in LiBrO3?
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