In ClO4-, the oxidation number of Cl is +7, and the oxidation number of each O is -2.
The oxidation number of Cl in ClO4- is +7. This is because oxygen usually has an oxidation number of -2 and there are four oxygen atoms in ClO4-, giving a total of -8. Since the overall charge of the ion is -1, the oxidation number of Cl must be +7 to balance the charges.
The oxidation number of Ag in AgClO4 is +1, as it is a common oxidation state for silver in compounds. The oxidation number of Cl in AgClO4 is +7, as it is in the ClO4- ion which has a total charge of -1.
The oxidation number of chlorine in ClO4 is +7. Each oxygen atom has an oxidation number of -2 and the overall charge of the ion is -1, which means the oxidation number of chlorine must be +7 to balance the charge.
The overall charge is -1. Oxidation number of oxygen in -2. By balancing the charges, chlorine is in +7 state.
In ClO4-, the oxidation number of Cl is +7, and the oxidation number of each O is -2.
The oxidation number of Cl in ClO4- is +7. This is because oxygen usually has an oxidation number of -2 and there are four oxygen atoms in ClO4-, giving a total of -8. Since the overall charge of the ion is -1, the oxidation number of Cl must be +7 to balance the charges.
The oxidation number of Ag in AgClO4 is +1, as it is a common oxidation state for silver in compounds. The oxidation number of Cl in AgClO4 is +7, as it is in the ClO4- ion which has a total charge of -1.
The oxidation number of chlorine in ClO4 is +7. Each oxygen atom has an oxidation number of -2 and the overall charge of the ion is -1, which means the oxidation number of chlorine must be +7 to balance the charge.
The overall charge is -1. Oxidation number of oxygen in -2. By balancing the charges, chlorine is in +7 state.
The oxidation number of Mn in Mn(ClO4)3 is +7. Each Cl has an oxidation state of -1 and each O has an oxidation state of -2. The sum of the oxidation numbers should equal the charge of the molecule, which is 0 in this case.
The oxidation number for Cl in ClO4 is +7. The overall charge of the ion is -1, so the oxidation number for O is -2. The sum of the oxidation numbers must add up to the overall charge of the ion.
Manganese has an oxidation state of +7, chlorine has an oxidation state of +7, and oxygen has an oxidation state of -2 in Mn(ClO4)3.
The oxidation number of each oxygen atom in ClO4- is -2. Since there are 4 oxygen atoms in ClO4-, and the total charge of the ion is -1, the oxidation number of oxygen must be adjusted to achieve the net charge, giving an oxidation number of +6 for the central chlorine atom.
ClO2- shows a disproportionation reaction because in this species, the oxidation state of chlorine is in between -1 (in Cl-) and +4 (in ClO4-), which allows for both oxidation and reduction to occur in the same compound. ClO4- does not undergo disproportionation as the oxidation state of chlorine is already at its highest state, +7, making further oxidation not possible.
The oxidation number of Cl in potassium chlorate (KClO3) is +5. This is because the oxidation number of K is +1 and the oxidation number of O is -2. By using the sum of the oxidation numbers in the compound, the oxidation number of Cl can be calculated to be +5.
The oxidation number for Cl in Cl4 is -1. Since Cl is a halogen, it typically has an oxidation number of -1 when it forms compounds.