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How many atoms are in 5.22 g of phosporous?
To find the number of atoms in 5.22 g of phosphorus, you first need to determine the number of moles of phosphorus by dividing the given mass by the molar mass of phosphorus (31.0 g/mol). From there, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen 3.161 g of phosphorus and 6.531 g of oxygen?
The molar mass of hydrogen is 1 g/mol, phosphorus is 31 g/mol, and oxygen is 16 g/mol. Calculate the number of moles of each element: hydrogen (0.3086 g / 1 g/mol), phosphorus (3.161 g / 31 g/mol), oxygen (6.531 g / 16 g/mol). Divide each number of moles by the smallest number of moles to get the mole ratio. The empirical formula is then H3PO4.
How many phosphorus atoms are contained in 158 kg of phosphorus?
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
What is the number of moles of argon in 607 g of argon?
the equation is Xg multiplied by the moles/grams of X = moles of X (the grams cancel leaving you with moles) 607g Ar x 1 mole/ 39.95g = 15.19 moles
How many phosphorus atoms does it take to equal 30.973 grams?
To determine the number of phosphorus atoms in 30.973 grams, you would first convert the mass to moles using the molar mass of phosphorus (30.973 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of phosphorus atoms, which would be 30.973 grams / 30.973 g/mol * 6.022 x 10^23 atoms/mol.
How many moles of phosphorus atoms are in a 100 g sample of phosphorus?
The molar mass of phosphorus is approximately 31 g/mol. To find the number of moles in a 100 g sample, divide the mass by the molar mass: 100 g / 31 g/mol = 3.23 mol. Therefore, there are approximately 3.23 moles of phosphorus atoms in a 100 g sample of phosphorus.
How many moles of phosphorus?
The number of moles of phosphorus depends on the given quantity or mass of phosphorus. To calculate the number of moles, you need to know the molar mass of phosphorus (about 30.97 g/mol) and the mass of the sample. You can then use the formula moles = mass/molar mass to find the number of moles.
How many atoms are in 5.22 g of phosporous?
To find the number of atoms in 5.22 g of phosphorus, you first need to determine the number of moles of phosphorus by dividing the given mass by the molar mass of phosphorus (31.0 g/mol). From there, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
How many moles of phosphorus atoms are in 100 grams of P4S10?
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
What is the empirical formula of a phosphoric acid that contains 0.3086 g of hydrogen 3.161 g of phosphorus and 6.531 g of oxygen?
The molar mass of hydrogen is 1 g/mol, phosphorus is 31 g/mol, and oxygen is 16 g/mol. Calculate the number of moles of each element: hydrogen (0.3086 g / 1 g/mol), phosphorus (3.161 g / 31 g/mol), oxygen (6.531 g / 16 g/mol). Divide each number of moles by the smallest number of moles to get the mole ratio. The empirical formula is then H3PO4.
How many grams of phosphorus trichloride are present in 3.42 moles of this compound?
3,42 moles of phosphorus trichloride have 469,6686 g.
How many moles in 2.3 grams of phosphorus?
To find the number of moles in 2.3 grams of phosphorus, we divide the mass by the molar mass of phosphorus, which is approximately 30.97 g/mol. So, 2.3 grams / 30.97 g/mol ≈ 0.074 moles.
How many moles of sodium hydroxide are found in 120 grams of Na OH?
To find the number of moles in 120 grams of NaOH, first calculate the molar mass of NaOH (sodium: 22.99 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol) which is 40 g/mol. Then, divide the given mass (120 g) by the molar mass to get the number of moles: 120 g / 40 g/mol = 3 moles of NaOH.
How many grams of phosphorus are present in 4.70 moles of tetraphosphorus decaoxide?
4,70 moles of tetraphosphorus decaoxide contain 582,56 g phosphorus.
How many moles of calcium represent in 120 grams?
120 g calcium is equal to 3 moles.
How many atoms of phosphorus are in a 0.577 g sample?
1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
How many phosphorus atoms are contained in 158 kg of phosphorus?
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
