nahco3 + ch3cooh --> co2 + CH3COONa + h2o
Note: it is CH3COONa (sodium acetate) and not na2co3(sodium carbonate) as stated in the question above
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The neutralization equation for the reaction between acetyl salicylic acid (HC5H7O4CO2) and sodium bicarbonate (NaHCO3) is: HC5H7O5CO2 + NaHCO3 -> NaC9H7O4 + H2O + CO2.
C6H8O7 + 3NAHCO3 = NA3C6H5O7 + 3H2CO3 ....This is the answer you are looking for
You need to double the Carbon Dioxide on the right side of the equation to make it balance....
NaHCO3+CH3COOH = 2CO2+H2O+NaCH3
The balanced equation for the reaction between nitric acid (HNO3) and sodium hydrogencarbonate (NaHCO3) is: HNO3 + NaHCO3 -> NaNO3 + H2O + CO2
The balanced equation for the dissolution of solid sodium hydrogen carbonate (NaHCO3) in water is: NaHCO3 (s) -> Na+ (aq) + HCO3- (aq)
Salicylic acid is soluble in NaOH and insoluble in NaHCO3 and HCl. In NaOH, salicylic acid can form a salt through neutralization. In NaHCO3 and HCl, salicylic acid remains as a solid due to its low solubility in these solutions.
The balanced chemical equation for the reaction between sodium bicarbonate (NaHCO3) and hydrochloric acid (HCl) is: NaHCO3 + HCl → NaCl + H2O + CO2
The net equation when MgCl2 reacts with NaHCO3 is MgCO3 + 2NaCl. Magnesium bicarbonate is not formed in this reaction.