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∙ 10y agoThe net ionic equation for the given reaction is: 2Au3+ + 3Sn → 3Sn2+ + 2Au. In this reaction, gold (III) ions are reduced to form gold solid, while tin solid is oxidized to form tin (II) ions. Only the ions that participate in the reaction are included in the net ionic equation.
The balanced chemical equation for the reaction between gold (Au) and hydrochloric acid (HCl) is: 2Au + 6HCl -> 2AuCl3 + 3H2
The balanced equation for Au + FeSO4 is Au + FeSO4 -> Au2(SO4)3 + Fe.
The Merrill-Crowe process is a method used for the precipitation of gold and silver from cyanide solutions. The chemical equation for the process involves the addition of zinc dust to the solution, which reacts with the gold and silver cyanide complexes, forming a zinc-gold/silver precipitate and releasing cyanide ions back into the solution to be reused.
Probably nothing as gold is not very reactive. 2Au + 6HCl -> 2AuCl3 + 3H2 This hypothetical reaction with gold's normal 3 oxidation state would probably never be seen in nature.
2Au + 4KCN + O2 → 2KAu(CN)2
The balanced chemical equation for the reaction between gold (Au) and hydrochloric acid (HCl) is: 2Au + 6HCl -> 2AuCl3 + 3H2
This is a redox reaction where gold (Au) is oxidized to Au2+ ions while copper (Cu) is reduced to Cu(s). The reaction involves the transfer of electrons from gold to copper, resulting in the formation of gold ions and solid copper.
The balanced equation for Au + FeSO4 is Au + FeSO4 -> Au2(SO4)3 + Fe.
The Merrill-Crowe process is a method used for the precipitation of gold and silver from cyanide solutions. The chemical equation for the process involves the addition of zinc dust to the solution, which reacts with the gold and silver cyanide complexes, forming a zinc-gold/silver precipitate and releasing cyanide ions back into the solution to be reused.
Probably nothing as gold is not very reactive. 2Au + 6HCl -> 2AuCl3 + 3H2 This hypothetical reaction with gold's normal 3 oxidation state would probably never be seen in nature.
2Au + 4KCN + O2 → 2KAu(CN)2
I'm not sure if you are asking about: e-ax2 or e-ax^2. Use the carets=^ in the future to raise something to a power.For e-ax2:You need to remember that: (ex)`= exalso: (eax)`= aeax, assuming a is a constant and not a function of x.Justrecognizeany constant drops down to the front.Therefore: (e-ax2)`=-2ae-ax2, treat the negative just as a constant or (-1)For e-ax^2: this one is a little bit trickier:We can just use u-substitution.Let u = x2.u` = 2xIf we substitute the u for x^2, we have: e-au , and we know the deriviate of that is -ae-2au, but we need to multiply by u` as well to get:(-ae-2au)(2x) = -2xae-2au, then we can just plug u back in.u = x2, so:-2xae-2au = -2xae-2ax^2And that is the answer.(e-ax^2)`= -2xae-2ax^2
When solid zinc reacts with aqueous gold(III) nitrate, zinc displaces gold in the compound through a single displacement reaction. The products of the reaction are gold metal and aqueous zinc nitrate.
Type your answer here... Al3+(aq) + 3e- Al(s) and Au(s) Au+(aq) + e-
Cu(s) | Cu2+(aq) Au+(aq) | Au(s)
When chlorine gas comes into contact with gold, a reaction occurs where the gold is oxidized by the chlorine to form a gold chloride compound. This reaction results in the formation of a white or yellowish gold chloride powder.
The asteroid belt has an average width of about 1 astronomical unit (AU), which is the distance from the Earth to the Sun. The asteroids in the belt are spread out over a large area, so there is no single diameter for the entire belt.