No, potassium does not have a noble gas electron configuration. The noble gas configuration for potassium would be [Ar] 4s¹, but instead, potassium has the electron configuration 1s² 2s² 2p^6 3s² 3p^6 4s¹.
The noble gas configuration for potassium is [Ar] 4s^1. To form a cation, potassium would lose its one valence electron, resulting in a 1+ ion. Therefore, the ion formed when potassium achieves a noble gas electron configuration is K^+.
Potassium forms a 1+ ion because it loses one electron to achieve a stable electron configuration like the nearest noble gas, argon. Calcium forms a 2+ ion by losing two electrons to attain a stable electron configuration like the nearest noble gas, argon.
The compound formed is KCl. K is in group 1 on the Periodic Table, it wants to lose 1 electron to be like the nearest noble gas (i.e. fulfill the octet rule - look at the Periodic Table to see what the closest noble gas is to the element in question, i.e. He, Ne, Ar, etc. In this case, K wants to lose 1 electron to be like Ar). Cl is in group 7 on the Periodic Table, it wants to gain 1 electron to be like the nearest noble gas (i.e. fulfill the octet rule). So, K is -1 Cl is +1 Put them together and they are perfectly happy (i.e. have fulfilled the octet rule). Another example, B reacting with Cl; B = group 3 = wants to lose 3 electrons to be like the nearest noble gas. Cl = group 7 = wants to gain 1 electron to be like the nearest noble gas. B is -3 Cl is +1 Therefore, BCl3 is the answer.
No, the noble gas notation for sulfur is [Ne] 3s2 3p4. This notation represents the electron configuration of sulfur using the nearest noble gas, which in this case is neon.
The noble gas nearest to Phosphorus (P) is Argon (Ar).
The ion formed when potassium achieves noble-gas electron configuration is K+ (potassium ion). This occurs when potassium loses one electron to have a full outer electron shell, similar to the nearest noble gas, argon.
No, potassium does not have a noble gas electron configuration. The noble gas configuration for potassium would be [Ar] 4s¹, but instead, potassium has the electron configuration 1s² 2s² 2p^6 3s² 3p^6 4s¹.
Potassium loses one electron to form K+ ion that has the noble gas configuration of the element neon.
This gas is neon.
No, a positive Potassium ion does not have noble gas stability. Noble gases have a full outer electron shell, but a positive Potassium ion (K+) has lost one electron and does not have a full outer shell.
The noble gas configuration for potassium is [Ar] 4s^1. To form a cation, potassium would lose its one valence electron, resulting in a 1+ ion. Therefore, the ion formed when potassium achieves a noble gas electron configuration is K^+.
Yes it is. Argon (atomic number 18) is the noble gas that is nearest to calcium (atomic number 20)
Potassium forms a 1+ ion because it loses one electron to achieve a stable electron configuration like the nearest noble gas, argon. Calcium forms a 2+ ion by losing two electrons to attain a stable electron configuration like the nearest noble gas, argon.
The noble gas electron configuration for potassium is [Ar] 4s^1. It represents the electron configuration of potassium by using the electron configuration of argon ([Ar] = 1s^2 2s^2 2p^6 3s^2 3p^6) as the noble gas core and then adding the additional 4s^1 electron for potassium.
Potassium has one valence electron that it would lose to become octet happy, or like a noble gas..therefore K(+1 charge)
The noble gas configuration of oxygen (O) is [He] 2s^2 2p^4, where [He] represents the electron configuration of the nearest noble gas, helium.