To find the mass of 5.0 moles of CH4, we first calculate the molar mass of CH4. The molar mass of CH4 is 16.05 g/mol. Multiplying this by the number of moles gives us 5.0 moles * 16.05 g/mol = 80.25 g. Therefore, the mass of 5.0 moles of CH4 is 80.25 grams.
Divide 96 by molecular mass.So the answer is 6mol
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
There are 1.52 x 10^24 molecules of CH4 in 2.52 mol of CH4.
300K
To find the mass of 5.0 moles of CH4, we first calculate the molar mass of CH4. The molar mass of CH4 is 16.05 g/mol. Multiplying this by the number of moles gives us 5.0 moles * 16.05 g/mol = 80.25 g. Therefore, the mass of 5.0 moles of CH4 is 80.25 grams.
5600
Divide 96 by molecular mass.So the answer is 6mol
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
7.48
There are 1.52 x 10^24 molecules of CH4 in 2.52 mol of CH4.
First, determine the heat of combustion for CH4, which is -802 kJ/mol. Then, calculate the number of moles of CH4 needed to emit 267 kJ of heat. Finally, convert the moles of CH4 to grams using the molar mass of CH4 (16 g/mol).
To calculate the mass of natural gas burned, we need to use the heat of combustion of methane, which is -890 kJ/mol. This means that 1 mol of CH4 produces 890 kJ of heat. Therefore, to emit 270 kJ of heat, you would need to burn 270/890 = 0.303 mol of CH4. The molar mass of CH4 is 16.05 g/mol, so the mass of CH4 needed would be 0.303 mol * 16.05 g/mol = 4.86 g.
Divide 96 by molecular mass.So the answer is 6mol
Carbon has a atomic mass of 12.So its percentage is 75%