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Is the percent by mass of copper in CuSO4 5H2O the same as in CuSO4?
No, the percent by mass of copper in CuSO4 5H2O will be different than in CuSO4 because CuSO4 5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4 5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4 5H2O compared to CuSO4.
What mass of anhydrous copper 2 sulfate can be obtained by heating 125g of cuper 2 sulfate pentahydrate?
To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.
What is the mass of 0.50 mol of CuSO4 5H20?
The molar mass of CuSO4 5H2O is 249.69 g/mol. Therefore, the mass of 0.50 mol of CuSO4 5H2O would be 0.50 mol * 249.69 g/mol = 124.85 grams.
What is the value of x if mass of CuSO4.xH2O and mass of CuSO4 is given after heated?
The value of x can be determined by comparing the masses of CuSO4.xH2O and CuSO4 before and after heating. By calculating the difference in mass, the value of x can be obtained based on the loss of water molecules during the heating process.
How many grams are there in 3 moles of CuSO4?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
Is the percent by mass of copper in CuSO4 5H2O the same as in CuSO4?
No, the percent by mass of copper in CuSO4 5H2O will be different than in CuSO4 because CuSO4 5H2O includes water molecules in addition to the copper sulfate compound itself. Therefore, the total mass of CuSO4 5H2O will be greater, resulting in a lower percent by mass of copper in CuSO4 5H2O compared to CuSO4.
What mass of anhydrous copper 2 sulfate can be obtained by heating 125g of cuper 2 sulfate pentahydrate?
To find the mass of anhydrous copper(II) sulfate obtained: Calculate the molar mass of each compound: CuSO4·5H2O (pentahydrate) and CuSO4 (anhydrous). Use the molar ratio between CuSO4 and CuSO4·5H2O to find the amount of anhydrous CuSO4. Convert the amount to mass using the molar mass of CuSO4. The mass of anhydrous CuSO4 will be less than the initial 125g due to the loss of water upon heating.
What is the mass of 0.50 mol of CuSO4 5H20?
The molar mass of CuSO4 5H2O is 249.69 g/mol. Therefore, the mass of 0.50 mol of CuSO4 5H2O would be 0.50 mol * 249.69 g/mol = 124.85 grams.
What is the value of x if mass of CuSO4.xH2O and mass of CuSO4 is given after heated?
The value of x can be determined by comparing the masses of CuSO4.xH2O and CuSO4 before and after heating. By calculating the difference in mass, the value of x can be obtained based on the loss of water molecules during the heating process.
How many grams are there in 3 moles of CuSO4?
The molar mass of CuSO4 is 159.6 g/mol. To find the mass of 3 moles of CuSO4, multiply the molar mass by the number of moles: 3 moles * 159.6 g/mol = 478.8 grams. Therefore, there are 478.8 grams in 3 moles of CuSO4.
What is the percent by mass of sulfur in CuSO4?
The molar mass of CuSO4 is 159.61 g/mol. The molar mass of sulfur (S) is 32.06 g/mol. To find the percent by mass of sulfur in CuSO4, we calculate: (32.06 g/mol / 159.61 g/mol) x 100% = 20.07%. Therefore, sulfur makes up about 20.07% of the mass of CuSO4.
What is the molar mass of CuSo4 x 5H2O?
The molar mass of CuSO4 x 5H2O (copper (II) sulfate pentahydrate) is calculated by adding the molar mass of CuSO4 (159.61 g/mol) to five times the molar mass of water (5 * 18.02 g/mol). Therefore, the molar mass of CuSO4 x 5H2O is 249.72 g/mol.
How many grams of copper sulfate pentahydrate CuSO4 5H2O would you heat to produce 29.8 g of water?
To calculate this, we first determine the molar mass of water (H2O) and copper sulfate pentahydrate (CuSO4 5H2O). Then we can use stoichiometry to find the mass of copper sulfate pentahydrate needed to produce 29.8g of water through the reaction.
What is the mass of 1 mole of cuso4?
159.6086g
How many moles are in 44.78 g of cupric sulfate?
To find the number of moles in 44.78 g of cupric sulfate (CuSO4), first calculate the molar mass of CuSO4. The molar mass of CuSO4 is 159.61 g/mol. Next, divide the given mass by the molar mass to find the number of moles. Therefore, 44.78 g ÷ 159.61 g/mol = 0.281 moles of CuSO4.
How many grams would 3.36 1023 molecules of copper (II) sulfate (CuSO4) weigh?
To calculate the weight of 3.36 x 10^23 molecules of CuSO4, you would first find the molar mass of CuSO4 (159.61 g/mol). Then, you'd use this molar mass to convert the number of molecules to grams using the formula: grams = (molecules x molar mass) / Avogadro's number. This would give you the weight of 3.36 x 10^23 molecules of CuSO4.
How many grams of copper sulfate would you heat to produce 29.8g of water?
To calculate the grams of copper sulfate needed to produce 29.8g of water, you need to consider the molar mass of water and copper sulfate. Then use stoichiometry to determine the amount of copper sulfate needed.
