The conversion of milliliters to grams depends on the density of the substance. For water, 180 milliliters is equivalent to 180 grams, as 1 milliliter of water weighs 1 gram.
The mass of 75 milliliters of water is approximately 75 grams, as the density of water is close to 1 gram per milliliter.
The balanced chemical equation for the combustion of octane is 2C8H18 + 25O2 --> 16CO2 + 18H2O. This means that 25 moles of O2 are required to completely burn 1 mole of octane. Since the molar mass of O2 is 32 g/mol, the amount of O2 needed to burn 19.8 g of octane is (25 moles O2 / 2 moles C8H18) * (32 g O2 / 1 mole O2) * (19.8 g C8H18). Therefore, the weight of oxygen required is 400.8 g.
To convert milliliters to gallons, divide the number of milliliters by 3,785.41. This is because there are approximately 3,785.41 milliliters in one gallon.
No, 100 milliliters and 100 grams are not the same. Milliliters measure volume, while grams measure mass. The relationship between milliliters and grams depends on the density of the substance being measured.
8750 ml
8750
To calculate the mass of octane burned, we can use the heat of combustion of octane which is 5470 kJ/mol. First, convert the given energy to kilojoules per mole. Then, use the molar mass of octane to convert moles to grams. This will give you the mass of octane that must be burned.
8750
729.1667
8800
8750
8750
87.5
To determine how many moles of octane are present in 16.0 g, you would divide the mass of octane by its molar mass. The molar mass of octane (C8H18) is approximately 114.23 g/mol. Therefore, 16.0 g รท 114.23 g/mol = 0.14 moles of octane.
The density of the metal is 8750 kg/mยณ. Density is calculated by dividing the mass of an object by its volume.
1750 Percentage = Rate x Base in this case the Rate is 20% or .20 and the Base is 8750.. so P= .20 x 8750 = 1750 therefore 1750 is the answer