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The Atomic Mass of the organic compound CH3OH is 12.0 + 3.0 + 16.0 + 1.0 = 32.0Amount of CH3OH = mass of pure sample/molar mass = 5.00/32.0 = 0.156molThere are 0.156 moles of CH3OH in a 5.00 gram pure sample.
To find the mass of 5.0 moles of CH4, we first calculate the molar mass of CH4. The molar mass of CH4 is 16.05 g/mol. Multiplying this by the number of moles gives us 5.0 moles * 16.05 g/mol = 80.25 g. Therefore, the mass of 5.0 moles of CH4 is 80.25 grams.
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How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
How many moles of CH4 are present in 6.07 g of (CH4)?
Divide 96 by molecular mass.So the answer is 6mol
- If the mass of 0.8 moles mixtures of NO and CH4 gases is 17 grams;I. The number of moles of NO is greater than the number of moles of CH4II. CH4 in the mix is 8 grams.III. NO in the mix is 0.3 mole?
I. False - Since both gases contribute to the total mass, the number of moles of NO does not necessarily need to be greater than the number of moles of CH4. II. True - If the total mixture mass is 17 grams and CH4 is 8 grams, then the remaining mass must be of NO. III. True - If the total moles of the mixture is 0.8, and CH4 is 0.5 moles (8g/16 g/mol), then the moles of NO would be the remaining 0.3 moles.
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
How many moles in 2.8mol CH4?
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
How many moles of CH4 are present in 6.07 g of (CH4)?
Divide 96 by molecular mass.So the answer is 6mol
- If the mass of 0.8 moles mixtures of NO and CH4 gases is 17 grams;I. The number of moles of NO is greater than the number of moles of CH4II. CH4 in the mix is 8 grams.III. NO in the mix is 0.3 mole?
I. False - Since both gases contribute to the total mass, the number of moles of NO does not necessarily need to be greater than the number of moles of CH4. II. True - If the total mixture mass is 17 grams and CH4 is 8 grams, then the remaining mass must be of NO. III. True - If the total moles of the mixture is 0.8, and CH4 is 0.5 moles (8g/16 g/mol), then the moles of NO would be the remaining 0.3 moles.
What mass of oxygen is required to completely react with 20 grams of CH4?
To calculate the mass of oxygen required to react with 20 grams of CH4, we first need to write and balance the chemical equation for the reaction. The balanced equation for the combustion of CH4 is: CH4 + 2O2 → CO2 + 2H2O This equation tells us that 1 mole of CH4 reacts with 2 moles of O2. The molar mass of CH4 is 16 g/mol. Therefore, 20 grams of CH4 is equal to 20/16 = 1.25 moles CH4. So, 1.25 moles of CH4 would require 2.50 moles of O2. The molar mass of O2 is 32 g/mol. Therefore, the mass of O2 required would be 2.50 moles * 32 g/mol = 80 grams.
How many moles in 64 grams of CH4?
There are 0.75 moles in it.You have to devide 12 by molecular mass
What is the weight in grams in o.4 moles of CH4?
This mass is 6,416 g.
What mass of CO2 is produced in the reaction of 4 moles of CH4 in excess O2?
For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
How many moles in 2.8mol CH4?
2,8 moles is of course equivalent to 2,8 moles !Probable is a spelling error in your question.
What mass of natural gas CH4 must you burn to emit 267 kJ of heat?
First, determine the heat of combustion for CH4, which is -802 kJ/mol. Then, calculate the number of moles of CH4 needed to emit 267 kJ of heat. Finally, convert the moles of CH4 to grams using the molar mass of CH4 (16 g/mol).
How many moles 64 grams of ch4?
First, determine molar mass of CH4: C:12g/mol + 4x H:1g/mol= 16g/mol Then divide by the number of grams. 64g/(16g/mol)= 4 moles of CH4
How many moles of oxygen will be needed to completely oxidize 64g CH4?
To calculate the moles of oxygen needed to completely oxidize 64g of CH4, first determine the moles of CH4 (64g / molar mass of CH4). Then, use the balanced chemical equation for the combustion of methane (CH4 + 2O2 -> CO2 + 2H2O) to find the mole ratio between CH4 and O2 (1 mole CH4 : 2 moles O2). Finally, multiply the moles of CH4 by the mole ratio to find the moles of O2 needed.
What is the atomic mass in grams of 0.35 moles of CH4?
I think you are asking for the mass of 0.35 moles of methane (CH4). First, we find the molecular mass of methane by addin the masses of all of the atoms. A carbon is 12, and each H is 1, so the molecular mass of CH4 is 16g/mole. Now we multiply 0.35 moles by 16 g/mole. The moles cancel out, and we have 5.6 g.
