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To calculate the mass of 9.32x10^24 molecules of methanol (CH3OH), you can first find the molar mass of CH3OH, which is approximately 32 g/mol. Then, you can convert the number of molecules to moles and finally to grams. The calculation would be (9.32x10^24 molecules) / (6.022x10^23 molecules/mol) * (32 g/mol) = 497 grams.
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What is the mass (in grams) of 9.85x10 to the 24 of methanol (CH3OH)?
To calculate the mass of methanol (CH3OH), we first need to find the molar mass of CH3OH. The molar mass of CH3OH is approximately 32 grams per mole. By multiplying the molar mass by the given amount of 9.85x10^24 molecules, we can find the mass in grams, which is about 3.15x10^26 grams.
What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?
To find the mass of 9.03 x 10^24 molecules of methanol (CH3OH), we first calculate the molar mass of CH3OH: (1 x 12.01 g/mol) + (4 x 1.01 g/mol) + (1 x 16.00 g/mol) = 32.04 g/mol Then we can convert the number of molecules to moles and finally to grams: 9.03 x 10^24 molecules * (1 mol / 6.022 x 10^23 molecules) * 32.04 g/mol ≈ 482 g
What is the mass in grams of 9.93x1024 molecules of methanol CH3OH?
To find the mass of 9.93x10^24 molecules of methanol (CH3OH), first calculate the molar mass of methanol: carbon's atomic mass = 12.01 g/mol, hydrogen = 1.01 g/mol, oxygen = 16.00 g/mol. Add the atomic masses together for the molar mass. Then, divide the number of molecules by Avogadro's number to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams.
How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 1.5 M CH3OH?
To prepare a 1.5 M solution of CH3OH in 150 mL, you need to calculate the moles required first. 1.5 moles/L * 0.15 L = 0.225 moles of CH3OH. Since the molar mass of CH3OH is 32 g/mol, you would need 7.2 grams of CH3OH to prepare the solution.
What is the mass of 3.62 X 1024 molecules of CH3OH?
To find the mass of 3.62 x 10^24 molecules of CH3OH, you need to first calculate the molar mass of CH3OH, which is 32.04 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert the number of molecules to moles. Finally, multiply the number of moles by the molar mass to find the mass.
What is the mass (in grams) of 9.85x10 to the 24 of methanol (CH3OH)?
To calculate the mass of methanol (CH3OH), we first need to find the molar mass of CH3OH. The molar mass of CH3OH is approximately 32 grams per mole. By multiplying the molar mass by the given amount of 9.85x10^24 molecules, we can find the mass in grams, which is about 3.15x10^26 grams.
What is the mass (in grams) of 9.18 1024 molecules of methanol (CH3OH)?
9.18x10^24 molecules CH3OH x 1 mole/6.02x10^23 molecules x 32 g/mole = 488 g (to 3 sig figs)
What is the mass in grams of 9.03 X 1024 molecules of methanol CH3OH?
To find the mass of 9.03 x 10^24 molecules of methanol (CH3OH), we first calculate the molar mass of CH3OH: (1 x 12.01 g/mol) + (4 x 1.01 g/mol) + (1 x 16.00 g/mol) = 32.04 g/mol Then we can convert the number of molecules to moles and finally to grams: 9.03 x 10^24 molecules * (1 mol / 6.022 x 10^23 molecules) * 32.04 g/mol ≈ 482 g
What is the mass (in grams) of methanol of 9.09x1024 molecules of methanol?
The mass is 483,62 g.
What mass of methanol (CH3OH) is produced when 140.1 g of carbon monoxide reacts with 12.12 g of hydrogen?
8.20g of carbon monoxide, how many grams of methanol will be produced?
What is the mass in grams of 9.93x1024 molecules of methanol CH3OH?
To find the mass of 9.93x10^24 molecules of methanol (CH3OH), first calculate the molar mass of methanol: carbon's atomic mass = 12.01 g/mol, hydrogen = 1.01 g/mol, oxygen = 16.00 g/mol. Add the atomic masses together for the molar mass. Then, divide the number of molecules by Avogadro's number to find the number of moles, and finally, multiply the number of moles by the molar mass to get the mass in grams.
What is the mass(in grams) of 9.401024 molecules of methanol?
The answer is 50,196 g.
What is the mass in grams of 9.47 x 1024 molecules of methonal?
To find the mass of 9.47 x 10^24 molecules of methanol, you first need to calculate the molar mass of methanol (CH3OH), which is approximately 32 g/mol. Then, use Avogadro's number to convert molecules to moles, and finally multiply by the molar mass to get the mass in grams.
How many grams of CH3OH must be added to water to prepare 150 mL of a solution that is 1.5 M CH3OH?
To prepare a 1.5 M solution of CH3OH in 150 mL, you need to calculate the moles required first. 1.5 moles/L * 0.15 L = 0.225 moles of CH3OH. Since the molar mass of CH3OH is 32 g/mol, you would need 7.2 grams of CH3OH to prepare the solution.
What is the mass of 3.62 X 1024 molecules of CH3OH?
To find the mass of 3.62 x 10^24 molecules of CH3OH, you need to first calculate the molar mass of CH3OH, which is 32.04 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert the number of molecules to moles. Finally, multiply the number of moles by the molar mass to find the mass.
How much NH3 is needed to react exactly with 21 grams of CH3OH?
To calculate the amount of NH3 needed to react with 21 grams of CH3OH, you first need to balance the chemical equation for the reaction. Then, you convert the mass of CH3OH to moles and use the mole ratio from the balanced equation to determine the moles of NH3 required. Finally, convert the moles of NH3 to grams using the molar mass of NH3.
How many grams of ch3oh must be added to water to prepare 150 ml of a solution that is 2.0 m ch3oh?
The answer is 9.6 grams.
