Do you mean: Na+Cl- + K+N03- --------> K+Cl- + Na+NO3-
Sodium + Potassium ---> Potassium + Sodium
Chloride Nitrate Chloride Nitrate
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The ionic equation for NaCl(aq) + KNO3(aq) is Na+(aq) + Cl-(aq) + K+(aq) + NO3-(aq) --> Na+(aq) + NO3-(aq) + K+(aq) + Cl-(aq). This equation represents the dissociation of the ions in the solution.
The skeleton equation for sodium nitrate (NaNO3) plus potassium chloride (KCl) is NaNO3 + KCl -> NaCl + KNO3.
The total ionic equation for NaCl + AgNO3 is: Na⁺ + Cl⁻ + Ag⁺ + NO₃⁻ → AgCl + Na⁺ + NO₃⁻
To balance the given chemical equations, follow these steps: NaCl + KNO3 → NaCl + KNO3 (already balanced) NaCl + AgNO3 → NaCl + AgNO3 (already balanced) NaOH + HCl → NaCl + H2O Na2CO3 + 2HCl → 2NaCl + H2O + CO2 BaCl2 + H2SO4 → BaSO4 + 2HCl CuSO4 + Zn(NO3)2 → Cu(NO3)2 + ZnSO4
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
The net ionic equation for the reaction between KCl(aq) and Pb(NO3)2(aq) to form KNO3(aq) and PbCl2(s) is: 2K^+(aq) + 2NO3^-(aq) + Pb^2+(aq) + 2Cl^-(aq) -> 2K^+(aq) + 2NO3^-(aq) + PbCl2(s)