Boron is a chemical with a symbol of B and an atomic number of 5. The equivalent weight of boron is dependent on the chemical that it is combining with.
Wiki User
∙ 9y agoThe equivalent weight of boron is approximately 10.81 g/mol. This value is calculated based on the atomic weight of boron (10.81 g/mol) and its valency.
Anonymous
*Eq. Weight of element =atomic weight /valency of element
*Eq. Weight of boron =11/3=3.666
The atomic weight of boron is approximately 10.81 grams per mole.
The atomic weight of boron is approximately 10.81 atomic mass units.
The lightest metalloid in the periodic table is boron with an atomic number of 5 and an atomic weight of approximately 10.81.
Boron's atomic weight is 10.81 grams per mole.
The scientific name for boron is simply "boron." It is a chemical element with the symbol B and atomic number 5.
The atomic weight of boron is approximately 10.81 grams per mole.
The atomic weight of boron is approximately 10.81 atomic mass units.
10.811
The lightest metalloid in the periodic table is boron with an atomic number of 5 and an atomic weight of approximately 10.81.
1.17
Boron's atomic weight is 10.81 grams per mole.
10.811 g/mol
Boron is the atom that contains 5 protons.
There are two isotopes of boron: boron-10 and boron-11 Both have 5 protons and 5 electrons per atomBoron-10 has 5 neutrons and boron-11 has 6 neutronsOverall this gives an atomic weight of 10.8 gmol-1
The scientific name for boron is simply "boron." It is a chemical element with the symbol B and atomic number 5.
Naturally occurring boron consists of two isotopes: boron-10 and boron-11. The average atomic weight of these isotopes is about 10.8. However, normal boron, which is primarily used in industrial applications, is often enriched to have a higher concentration of boron-10 for specific purposes, such as neutron shielding or in nuclear reactors. By enriching the boron with a higher percentage of boron-10, its properties can be tailored to meet the requirements of these specialized applications.
To find the number of moles in 97.2 grams of boron, you need to divide the mass given by the molar mass of boron. The molar mass of boron is approximately 10.81 g/mol. Therefore, 97.2 grams of boron is equal to 97.2/10.81 ≈ 8.98 moles.