CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
C5H10 can be both an alkane and an alkene. As an alkane, it would be pentane (C5H12), and as an alkene, it would be 1-pentene (C5H10). The presence or absence of a double bond in the molecule determines if it is an alkane or an alkene.
The empirical formula for C12H12 is CH. The empirical formula represents the simplest whole-number ratio of elements in a compound.
The density or some other information must be given that allow you to find the molar mass. Calculate the empirical formula mass. Divide molar mass by empirical formula mass. This answer is multiplied by all subscripts of the empirical formula to get the molecular formula.
The empirical formula for catechol is C6H6O2.
CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
CH2 is the empirical formula for C4H8 because it is an alkene and the empirical fomula for ALL alkenes are C(n)H(2n) n being the number of molecules!!! (^-^)
It is an empirical formula.
C5H10 can be both an alkane and an alkene. As an alkane, it would be pentane (C5H12), and as an alkene, it would be 1-pentene (C5H10). The presence or absence of a double bond in the molecule determines if it is an alkane or an alkene.
The empirical formula for C12H12 is CH. The empirical formula represents the simplest whole-number ratio of elements in a compound.
A formula unit is an empirical formula.
An empirical formula has no data about the structure of a compound.
It Has No Empirical Formula.
In this instance, the empirical formula is the same as the formula unit: NaNO3
It has a molecular formula of C10H8 so that would make an empirical formula of C5H4.
The empirical formula for potassium manganate is KMnO4.
The density or some other information must be given that allow you to find the molar mass. Calculate the empirical formula mass. Divide molar mass by empirical formula mass. This answer is multiplied by all subscripts of the empirical formula to get the molecular formula.