The concentration of a solution is given by the formula: concentration = moles of solute / volume of solution in liters. However, to determine the concentration in this case, we need to know the moles of HCl in the solution. Given that the concentration is 0.5 M, it means there are 0.5 moles of HCl in every liter of solution. To find out how many moles are in 400 ml (0.4 L) of 0.5 M HCl solution, we use the formula: moles = concentration x volume. moles = 0.5 M x 0.4 L = 0.2 moles. Therefore, the concentration of 400 ml of 0.5 M HCl solution is 0.5 M.
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
To make 25 ml of 0.0010 M HCl from 0.010 M HCl: (0.010 M) x V1 = (0.0010 M) x 25 ml V1 = (0.0010 M * 25 ml) / 0.010 M V1 = 2.5 ml of the 0.010 M HCl solution should be diluted to 25 ml to get 0.0010 M HCl.
To prepare a liter of 0.5N HCl solution, you would measure 50 mL of concentrated hydrochloric acid (37% HCl by mass) and dilute it to 1 liter with distilled water.
You can dilute the 1N HCl solution by adding 999 parts of water to 1 part of the 1N HCl solution. For example, take 1 mL of 1N HCl and add it to 999 mL of water to create a 0.001N HCl solution.
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
100 M HCl don't exist.
To make 0.25N HCl from 1.00N HCl, you would need to dilute the 1.00N HCl solution by adding three parts of water for every part of the original solution. For example, you can mix 1 mL of 1.00N HCl with 3 mL of water to obtain 0.25N HCl solution.
0.0747mol/L of HCL 1.81mol/L of water
Mix 125 mL 0,1 N HCl with 125 mL water.
To make 25 ml of 0.0010 M HCl from 0.010 M HCl: (0.010 M) x V1 = (0.0010 M) x 25 ml V1 = (0.0010 M * 25 ml) / 0.010 M V1 = 2.5 ml of the 0.010 M HCl solution should be diluted to 25 ml to get 0.0010 M HCl.
To prepare a liter of 0.5N HCl solution, you would measure 50 mL of concentrated hydrochloric acid (37% HCl by mass) and dilute it to 1 liter with distilled water.
You can dilute the 1N HCl solution by adding 999 parts of water to 1 part of the 1N HCl solution. For example, take 1 mL of 1N HCl and add it to 999 mL of water to create a 0.001N HCl solution.
520 ml of HCl in 480 ml of water=1000ml = 5 N
To prepare 100 mL of 1.0 M HCl from a 3.0 M stock solution, you can use the formula: (M_1V_1 = M_2V_2). Solving for V1: (3.0 M)(V1 mL) = (1.0 M)(100 mL), thus V1 = 33.3 mL. So, you would need to measure out 33.3 mL of the 3.0 M HCl solution and then dilute it to 100 mL to obtain 1.0 M HCl.
400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.400 L/250 mL = 400,000 mL / 250 mL = 1600 bottles.
To prepare 500 ml of 1N HCl from 10N HCl, you need to dilute the 10N HCl with distilled water. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial concentration needed, C2 is the final concentration, and V2 is the final volume. In this case, the calculation would be 10 x V1 = 1 x 500. Solve for V1 to find the volume of 10N HCl needed, then add distilled water to make a total volume of 500 ml.
To find the moles of HCl, first calculate the millimoles of HCl in 50 mL: 4.0 mol/L * 50 mL = 200 mmol. Then convert millimoles to moles by dividing by 1000: 200 mmol / 1000 = 0.2 moles of HCl. Therefore, there are 0.2 moles of HCl in 50 mL of 4.0 M HCl.