What is the complete ionic equation of sodium carbonate and sulfuric acid?

Answer 1

The chemical equation is

2NaHCO3 (s) + H2SO4 (aq) --> Na2SO4(aq) + 2CO2 (g) + 2H2O (l)

The work equation is

Two moles of solid sodium bicarbonate (sodium hydrogen carbonate) plus one mole of aqueous sulfuric acid produces one mole of aqueous sodium sulfate plus two moles of carbon dioxide gas, and two moles of liquid water.

Answer 2

H2SO4(aq) + Na2CO3(aq) --> Na2SO4(aq) + H2O(l) + CO2(g)

Answer 3

The chemical equation is:
2 Na+ (CO3)2- + 2 H+ + (SO4)2- = 2 Na+ + (SO4)2- + H2O + (CO3)-

Answer 4

The complete ionic equation for sodium carbonate (Na2CO3) and sulfuric acid (H2SO4) reacting is:

2Na+ (aq) + CO3^2- (aq) + 2H+ (aq) + SO4^2- (aq) → 2Na+ (aq) + 2SO4^2- (aq) + H2O (l) + CO2 (g)

Answer 5

The reaction between sodium carbonate and sulfuric acid is:

H2SO4 + Na2CO3 --> Na2SO4 + CO2 + H2O

The products are sodium sulfate, carbon dioxide, and water.

Answer 6

The reaction of sodium carbonate and hydrochloric acid is 2HCl + Na2CO3 --> 2NaCl + CO2 + H2O

Answer 7

The reaction is:
2 NaHCO3 + H2SO4 = Na2SO4 + 2 CO2 + 2 H2O

Answer 8

AgHCO3

Answer 9

H+ (aq) + OH- (aq) --> H2O (l)

Answer 10

Na2CO3 + H2SO4 = Na2SO4 + H2O +CO2