C3H6 is an empirical formula for propene.
The balanced equation for the combustion of polypropylene (C3H6)n is: C3H6 + 4.5O2 -> 3CO2 + 3H2O
The empirical formula for propene (C3H6) is CH2. This is found by dividing the subscripts of each element by their greatest common factor, which in this case is 3.
There are 9 atoms in C3H6: 3 carbon atoms and 6 hydrogen atoms.
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
The balanced equation of C3H6 + O3 => CO + H2O is C3H6 + 2O3 => 3CO + 3H2O.
C3H6 is an empirical formula for propene.
The formula for propene is C3H6. It is an unsaturated hydrocarbon with a double bond between two carbon atoms.
The balanced equation for the combustion of polypropylene (C3H6)n is: C3H6 + 4.5O2 -> 3CO2 + 3H2O
The empirical formula for propene (C3H6) is CH2. This is found by dividing the subscripts of each element by their greatest common factor, which in this case is 3.
There are 9 atoms in C3H6: 3 carbon atoms and 6 hydrogen atoms.
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
alkane
C3H6 is the chemical formula of propylene and CH2 is the chemical formula of the group methylene or carbene.
Formula: C3H6
Those with double or triple carbon bonds, so that would be C2H4 and C3H6.
Formula: C3H6