The chemical formula for copper(II) nitrate is Cu(NO3)2.
The chemical formula for Iron (II) phosphide is Fe3P2.
The formula V3S3 corresponds to trivanadium trisulfide. It is a chemical compound composed of three vanadium (V) atoms and three sulfur (S) atoms.
The chemical formula for the compound formed between scandium(III) and the bromate ion is Sc(BrO3)3. Each scandium(III) ion will combine with three bromate ions to achieve a neutral compound with a balanced charge.
it is Ni2 CL1then u switch the head numbers and it isNi(CL)2
The chemical formula for iron (lll) oxide is Fe2O3.
The chemical formula for copper(II) nitrate is Cu(NO3)2.
The chemical formula for Iron (II) phosphide is Fe3P2.
Indium(lll) bromide (InBr3)
Iron metal reacts with oxygen to form iron (III) oxide, also known as rust. This reaction is a redox reaction where iron is oxidized from its elemental state to Fe3+ ions. The chemical equation for this reaction is: 4Fe(s) + 3O2(g) -> 2Fe2O3(s)
Copper (III) doesn't exist; copper(II) arsenide is Cu3As2.
The chemical formula for chromium(III) phosphide is CrP. In this compound, chromium has a +3 charge, while phosphorus has a -3 charge.
Yes, Fe (iron) plus S (sulfur) equals FeS (iron sulfide). If the iron ion is iron(ll) then it is iron(ll) sulfide; if it is iron(lll), then it iron(lll) sulfide.
The formula for iron hydrogen carbonate is Fe(HCO3)2.
The chemical formula for ferrous chloride or iron (II) chloride is FeCl2.
Percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100. The theoretical yield can be calculated by stoichiometry. In this case, the theoretical yield of iron would be 43.3g. Therefore, the percent yield would be (15.0g / 43.3g) x 100 = 34.6%.
The formula V3S3 corresponds to trivanadium trisulfide. It is a chemical compound composed of three vanadium (V) atoms and three sulfur (S) atoms.