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The chemical formula for iron (lll) oxide is Fe2O3.

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βˆ™ 6y ago
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βˆ™ 5mo ago

The chemical formula for iron (III) oxide is Fe2O3. This compound consists of two iron atoms (Fe) and three oxygen atoms (O) bonded together. It is commonly known as rust.

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Q: What is the chemical formula for iron (lll) oxide?
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Related questions

What is the chemical formula for iron(lll) oxide?

The chemical formula for iron (lll) oxide is Fe2O3.


What is the chemical formula for CuNO3?

The chemical formula for copper(II) nitrate is Cu(NO3)2.


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What is the chemical formula for InBr3?

Indium(lll) bromide (InBr3)


What is the reaction of iron metal with oxygen to form Iron lll oxide?

Iron metal reacts with oxygen to form iron (III) oxide, also known as rust. This reaction is a redox reaction where iron is oxidized from its elemental state to Fe3+ ions. The chemical equation for this reaction is: 4Fe(s) + 3O2(g) -> 2Fe2O3(s)


What is the chemical formula for copper (lll) arsenide?

Copper (III) doesn't exist; copper(II) arsenide is Cu3As2.


What is achemical formula for choromium lll phosphide?

The chemical formula for chromium(III) phosphide is CrP. In this compound, chromium has a +3 charge, while phosphorus has a -3 charge.


Fe plus S FeS?

Yes, Fe (iron) plus S (sulfur) equals FeS (iron sulfide). If the iron ion is iron(ll) then it is iron(ll) sulfide; if it is iron(lll), then it iron(lll) sulfide.


Formula for iron hydrogen carbonate?

The formula for iron hydrogen carbonate is Fe(HCO3)2.


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The chemical formula for ferrous chloride or iron (II) chloride is FeCl2.


What is the percent yield for the reaction if 65.0 g of iron lll oxide produces 15.0g of iron?

Percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100. The theoretical yield can be calculated by stoichiometry. In this case, the theoretical yield of iron would be 43.3g. Therefore, the percent yield would be (15.0g / 43.3g) x 100 = 34.6%.


What is the name of the formula V3S3?

The formula V3S3 corresponds to trivanadium trisulfide. It is a chemical compound composed of three vanadium (V) atoms and three sulfur (S) atoms.