The trans isomer of potassium dioxalatodiaquachromate (III) is prepared by treating the cis isomer with ammonia gas in a concentrated ammonia solution. The chemical equation for the preparation is: Cr(C2O4)(H2O)2(NH3)2 + NH3 → Cr(C2O4)(H2O)2(NH3) + H2O + NH4NO3
The chemical equation is:2 KI + Cl2 = 2 KCl + I2
The chemical reaction between lead nitrate (Pb(NO3)2) and potassium sulfate (K2SO4) produces solid lead sulfate (PbSO4) and potassium nitrate (KNO3) in solution. The balanced chemical equation is: Pb(NO3)2 + K2SO4 -> PbSO4(s) + 2KNO3.
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
A chemical reaction occurs where iron III iodide is formed and potassium nitrate is produced as a byproduct. The balanced chemical equation for this reaction is 2KI + Fe(NO3)3 -> 2KNO3 + FeI3. Iron III iodide is a dark brown solid, whereas potassium nitrate remains in solution.
The trans isomer of potassium dioxalatodiaquachromate (III) is prepared by treating the cis isomer with ammonia gas in a concentrated ammonia solution. The chemical equation for the preparation is: Cr(C2O4)(H2O)2(NH3)2 + NH3 → Cr(C2O4)(H2O)2(NH3) + H2O + NH4NO3
The chemical equation is:2 KI + Cl2 = 2 KCl + I2
Potassium fluorine is represented as KF in a chemical equation. This compound consists of one potassium ion (K+) and one fluoride ion (F-). When it dissociates in a solution, it forms K+ and F- ions.
The chemical reaction between lead nitrate (Pb(NO3)2) and potassium sulfate (K2SO4) produces solid lead sulfate (PbSO4) and potassium nitrate (KNO3) in solution. The balanced chemical equation is: Pb(NO3)2 + K2SO4 -> PbSO4(s) + 2KNO3.
When chlorine gas is added to potassium iodide solution, potassium chloride and iodine are formed. The balanced chemical equation for this reaction is 2KI + Cl2 → 2KCl + I2.
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
A chemical reaction occurs where iron III iodide is formed and potassium nitrate is produced as a byproduct. The balanced chemical equation for this reaction is 2KI + Fe(NO3)3 -> 2KNO3 + FeI3. Iron III iodide is a dark brown solid, whereas potassium nitrate remains in solution.
The chemical equation is:2 (OH)- + Pb(2+) = PbOH)2(s)
The chemical equation for the reaction between acetic acid (CH3COOH) and potassium hydroxide (KOH) is: CH3COOH + KOH -> CH3COOK + H2O. This reaction is a neutralization reaction that forms potassium acetate (CH3COOK) and water (H2O).
Potassium iodide is used in the preparation of iodine solution to increase the solubility of iodine in water. It helps stabilize the iodine in solution by forming triiodide ions, which prevents iodine from sublimating back to a solid state. Additionally, potassium iodide helps to maintain a consistent concentration of iodine in the solution.
The chemical equation is C7H4O9
The reaction between barium chloride (BaCl2) and potassium sulfate (K2SO4) forms barium sulfate (BaSO4) and potassium chloride (KCl). The balanced chemical equation for this reaction is: BaCl2 + K2SO4 -> BaSO4 + 2KCl.