+2
The charge on chromium in the complex Cr(NH)Br is 3.
The oxidation number of Cr in Cr3+ is +3. This is because each Cl ion has a charge of -1, and since the compound is neutral, the total positive charge from Cr must equal the total negative charge from the Cl ions.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
Cr(CN)2
The oxidation number of Cr in CrO4^2- is +6. This can be calculated by considering the overall charge of the ion (-2) and the known charge of the oxygen ion (-2 each).
+2
The charge on chromium in the complex Cr(NH)Br is 3.
3 +
The oxidation number of Cr in Cr3+ is +3. This is because each Cl ion has a charge of -1, and since the compound is neutral, the total positive charge from Cr must equal the total negative charge from the Cl ions.
+6This compound has dichromate in it (Cr2O7-2). Oxygen almost always has an oxidation state of -2, which means the total charge for the oxygens is -14. The charge on the two chromates combined needs to be two less than the total charge on the oxygens because the ion has an overall charge of -2. Thus, the oxidation state for Cr is +6.
The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.
Cr(CN)2
The oxidation number of Cr in CrO4^2- is +6. This can be calculated by considering the overall charge of the ion (-2) and the known charge of the oxygen ion (-2 each).
Usually +2, but all the different charges (+3, +6) can be found in chromium's box on the table.
It depends on the offense. You can find specific information here: http://www.statutes.legis.state.tx.us/Docs/CR/htm/CR.12.htm
The transition metal with 24 electrons is chromium (Cr) and its common ion with a +3 charge is Cr3+.
The oxidation number of Cr in Cr2O7^2- ion is +6. Each oxygen atom has a -2 charge, and the overall charge of the ion is 2-, so combining the charges gives -2*(-7) = -14. Since the overall charge is 2-, the oxidation number of Cr must be +6 to balance the charges.