To write a balanced equation for the reaction between FeCl3 and Na2S, first determine the chemical formula for the products formed when they react. In this case, the products are Fe2S3 and NaCl. Then, write the balanced chemical equation by ensuring that the number of atoms of each element is the same on both sides of the equation. The balanced equation for FeCl3 + Na2S is 2FeCl3 + 3Na2S -> Fe2S3 + 6NaCl.
The balanced equation is 2HCl + Na2S → H2S + 2NaCl. This is balanced as the number of atoms of each element is the same on both sides of the equation.
The balanced equation for the reaction between sodium and sulfur is: 2 Na + S -> Na2S
The balanced molecular equation for the reaction between sodium sulfide (Na2S) and potassium iodide (KI) is: 2Na2S + 2KI -> 2NaI + K2S.
The balanced chemical equation is: Zn(NO3)2(aq) + Na2S(aq) -> ZnS(s) + 2 NaNO3(aq)
To write a balanced equation for the reaction between FeCl3 and Na2S, first determine the chemical formula for the products formed when they react. In this case, the products are Fe2S3 and NaCl. Then, write the balanced chemical equation by ensuring that the number of atoms of each element is the same on both sides of the equation. The balanced equation for FeCl3 + Na2S is 2FeCl3 + 3Na2S -> Fe2S3 + 6NaCl.
The balanced equation is 2HCl + Na2S → H2S + 2NaCl. This is balanced as the number of atoms of each element is the same on both sides of the equation.
The balanced equation for the reaction between sodium and sulfur is: 2 Na + S -> Na2S
The balanced molecular equation for the reaction between sodium sulfide (Na2S) and potassium iodide (KI) is: 2Na2S + 2KI -> 2NaI + K2S.
NaS2 is an unbalanced equation. It would need to be Na2S to be a balanced equation (two sodium, one sulfide). Na2S is Sodium Sulfide.
The balanced chemical equation for the reaction between mercury(II) nitrate and sodium sulfide is: Hg(NO3)2 + Na2S -> HgS + 2NaNO3
The balanced chemical equation is: Zn(NO3)2(aq) + Na2S(aq) -> ZnS(s) + 2 NaNO3(aq)
The balanced chemical equation for the decomposition of solid sodium sulfide (Na2S) in aqueous solution is: 2Na2S(s) -> 2NaOH(aq) + H2S(g)
Yes, nitric acid (HNO3) and sodium sulfide (Na2S) will react to form sodium nitrate (NaNO3) and hydrogen sulfide (H2S). The balanced chemical equation for the reaction is: 2HNO3 + Na2S → 2NaNO3 + H2S
The balanced equation for the reaction is: 2 Na2S (s) + 3 Cu(NO3)2 (aq) -> 4 NaNO3 (aq) + 3 CuS (s)
The balanced molecular equation is CaCl2 + Na2S -> CaS + 2NaCl. To write the ionic equation, we need to break down the reactants and products into their respective ions. This results in the ionic equation: Ca2+ + 2Cl- + 2Na+ + S2- -> CaS + 2Na+ + 2Cl-. Cross out spectator ions that appear on both sides of the equation to obtain the net ionic equation: Ca2+ + S2- -> CaS.
When sulfur (S) reacts with concentrated sodium hydroxide (NaOH), it forms sodium sulfide (Na2S) and water (H2O). The balanced chemical equation for this reaction is: S + 2NaOH -> Na2S + H2O.