The balanced equation for Aluminum sulfate and Potassium Hydroxide is Al2(SO4)3 + 6KOH → 2Al(OH)3 + 3K2SO4.
The balanced neutralization reaction between phosphorus acid (H3PO3) and aluminum hydroxide (Al(OH)3) produces aluminum phosphate (AlPO4) and water (H2O). The balanced chemical equation is: 2H3PO3 + 3Al(OH)3 → 2AlPO4 + 6H2O
The balanced equation for the reaction between aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl) in the stomach is: Al(OH)3 + 3HCl → AlCl3 + 3H2O This reaction forms aluminum chloride (AlCl3) and water (H2O).
The balanced chemical equation for the reaction between acetic acid (CH3COOH) and aluminum hydroxide (Al(OH)3) to form water and aluminum acetate (Al(CH3COO)3) is: 2CH3COOH + 3Al(OH)3 -> 3H2O + Al(CH3COO)3
The reaction between aluminum oxide and dilute potassium hydroxide produces potassium aluminum oxide and water. The balanced chemical equation for this reaction is: Al2O3 + 6KOH -> 2K3Al(OH)6.
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
The balanced equation for Aluminum sulfate and Potassium Hydroxide is Al2(SO4)3 + 6KOH → 2Al(OH)3 + 3K2SO4.
The balanced equation is: 2Al(NO3)3 + 6NaOH → 2Al(OH)3 + 6NaNO3 .
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
The balanced neutralization reaction between phosphorus acid (H3PO3) and aluminum hydroxide (Al(OH)3) produces aluminum phosphate (AlPO4) and water (H2O). The balanced chemical equation is: 2H3PO3 + 3Al(OH)3 → 2AlPO4 + 6H2O
The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and aluminum sulfate (Al2(SO4)3) is: 6 NaOH + Al2(SO4)3 -> 3 Na2SO4 + 2 Al(OH)3 This reaction forms sodium sulfate and aluminum hydroxide.
The balanced equation for the reaction between aluminum hydroxide (Al(OH)3) and hydrochloric acid (HCl) in the stomach is: Al(OH)3 + 3HCl → AlCl3 + 3H2O This reaction forms aluminum chloride (AlCl3) and water (H2O).
The balanced equation for the reaction between aluminum sulfide and water is: Al2S3 + 6H2O → 2Al(OH)3 + 3H2S. This reaction forms aluminum hydroxide and dihydrogen sulfide gas.
The balanced chemical equation for the reaction between acetic acid (CH3COOH) and aluminum hydroxide (Al(OH)3) to form water and aluminum acetate (Al(CH3COO)3) is: 2CH3COOH + 3Al(OH)3 -> 3H2O + Al(CH3COO)3
The reaction between aluminum oxide and dilute potassium hydroxide produces potassium aluminum oxide and water. The balanced chemical equation for this reaction is: Al2O3 + 6KOH -> 2K3Al(OH)6.
the balanced equation for ammonium hydroxide and perchloric acid is given below.NH4OH (aq) + HCl (aq) ---> NH4Cl (aq)+ H2O (l) .Above is the balanced molecular Equation.
The balanced equation for potassium hydroxide (KOH) and hydrochloric acid (HCl) is: KOH + HCl -> KCl + H2O