The oxidation number of Pt in PtCl6 is +4. Each Cl has an oxidation number of -1, and since the overall charge of the complex ion is 0, the oxidation number of Pt must be +4 to balance the charges.
The oxidation number for Pt in PtO is +2. Oxygen typically has an oxidation number of -2, so the sum of the oxidation numbers in PtO must be zero since it is a neutral compound.
The oxidation number of Pt in PtCl4^2- is +2. This is because the overall charge of the complex ion is 2-, and each chlorine atom has an oxidation state of -1, so the oxidation state of Pt must be +2 to balance the charge.
The oxidation number of Pt in K2PtCl6 is +4. In this compound, the total charge of potassium (K) is +2 (from 2*K+1), and the total charge of chloride (Cl) is -1 (from Cl-1), so the oxidation number of Pt must be +4 to balance the overall charge of the compound.
For PtCl6^2-, let x be the oxidation number of Pt, and -1 be the oxidation number of Cl. Since there are 6 Cl atoms each with an oxidation number of -1, the sum of the oxidation numbers must equal the charge of the ion, which is -2. Therefore, x + 6(-1) = -2. Solving for x, we get x = +4. So, the oxidation number of Pt in PtCl6^2- is +4.
The oxidation number of Pt in PtCl6 is +4. Each Cl has an oxidation number of -1, and since the overall charge of the complex ion is 0, the oxidation number of Pt must be +4 to balance the charges.
The oxidation number for Pt in PtO is +2. Oxygen typically has an oxidation number of -2, so the sum of the oxidation numbers in PtO must be zero since it is a neutral compound.
The oxidation number of Pt in PtCl4^2- is +2. This is because the overall charge of the complex ion is 2-, and each chlorine atom has an oxidation state of -1, so the oxidation state of Pt must be +2 to balance the charge.
The oxidation number of Pt in K2PtCl6 is +4. In this compound, the total charge of potassium (K) is +2 (from 2*K+1), and the total charge of chloride (Cl) is -1 (from Cl-1), so the oxidation number of Pt must be +4 to balance the overall charge of the compound.
For PtCl6^2-, let x be the oxidation number of Pt, and -1 be the oxidation number of Cl. Since there are 6 Cl atoms each with an oxidation number of -1, the sum of the oxidation numbers must equal the charge of the ion, which is -2. Therefore, x + 6(-1) = -2. Solving for x, we get x = +4. So, the oxidation number of Pt in PtCl6^2- is +4.
The oxidation number of Cl in PtCl4^2- is -1. This can be determined by considering that the overall charge of the complex ion is 2-, and each Cl atom has an oxidation number of -1.
The oxidation state of platinum (Pt) is usually +2 or +4. In some less common cases, platinum can also exhibit oxidation states of +0 and +6.
The oxidation state of Pt in PtCl62- is +4. This is because each Cl atom has an oxidation state of -1, and the overall charge of the complex ion is -2. Thus, the oxidation state of Pt can be calculated as follows: x + 6(-1) = -2, where x is the oxidation state of Pt. Solving for x gives x = +4.
Hydrogen's oxidation number is +1.Chlorin's oxidation number is +1.Oxygen's oxidation number is -2.
The oxidation number of acetate (CH3COO-) is -1. The carbon atom has an oxidation number of +3, each hydrogen atom has an oxidation number of +1, and the oxygen atoms have an oxidation number of -2.
The oxidation number of each hydrogen in H2CO2 is +1, while the oxidation number of each carbon in CO2 is +4. This is because hydrogen usually has an oxidation number of +1, and oxygen usually has an oxidation number of -2.
Silicon's oxidation number is +4.Oxygen's oxidation number is -2