In KMnO4, the oxidation number of potassium (K) is +1, the oxidation number of oxygen (O) is -2, and the overall molecule has a charge of 0. To find the oxidation number of manganese (Mn), we use the formula:
(oxidation number of K) + (oxidation number of Mn) + 4*(oxidation number of O) = 0.
This gives us: 1 + x + 4*(-2) = 0. Solving for x, the oxidation number of Mn in KMnO4 is +7.
The oxidation number of manganese (Mn) in KMnO4 is +7.
The oxidation number for oxygen in KMnO4 is -2. The total oxidation number for the compound must equal zero (since it is neutral), and since the oxidation number for potassium (K) is +1 and for manganese (Mn) is +7, the oxidation number for oxygen must be -2 to balance the charges.
The oxidation number of Mn in KMnO4 is +7. This is because oxygen (O) is typically assigned a -2 oxidation state, with the total oxidation state of the compound being 0. By following the rule that the sum of oxidation states in a compound is equal to the charge of the compound, we find that Mn is in the +7 oxidation state in KMnO4.
In KMnO4, Mn has an oxidation number of +7, KNO2 has N with an oxidation number of +3, and H2SO4 has S with an oxidation number of +6. In MnSO4, Mn has an oxidation number of +2, H2O has O with an oxidation number of -2, KNO3 has N with an oxidation number of +5, and K2SO4 has S with an oxidation number of +6.
The oxidation number of manganese (Mn) can vary depending on the compound it is in. In MnO2, the oxidation number of Mn is +4, while in KMnO4, the oxidation number of Mn is +7.
MnO2: oxidation number +4KMnO4: oxidation number +7
The oxidation number of manganese (Mn) in KMnO4 is +7.
The oxidation number for oxygen in KMnO4 is -2. The total oxidation number for the compound must equal zero (since it is neutral), and since the oxidation number for potassium (K) is +1 and for manganese (Mn) is +7, the oxidation number for oxygen must be -2 to balance the charges.
The oxidation number of Mn in KMnO4 is +7. This is because oxygen (O) is typically assigned a -2 oxidation state, with the total oxidation state of the compound being 0. By following the rule that the sum of oxidation states in a compound is equal to the charge of the compound, we find that Mn is in the +7 oxidation state in KMnO4.
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7
In KMnO4, Mn has an oxidation number of +7, KNO2 has N with an oxidation number of +3, and H2SO4 has S with an oxidation number of +6. In MnSO4, Mn has an oxidation number of +2, H2O has O with an oxidation number of -2, KNO3 has N with an oxidation number of +5, and K2SO4 has S with an oxidation number of +6.
The oxidation number of manganese (Mn) can vary depending on the compound it is in. In MnO2, the oxidation number of Mn is +4, while in KMnO4, the oxidation number of Mn is +7.
The oxidation number of Mn in KMnO4 is +7. This can be determined by assigning the known oxidation numbers of potassium (+1) and oxygen (-2) and solving for the unknown oxidation number of manganese.
To calculate the oxidation number of Mn in KMnO4, set up an equation using the known oxidation numbers of potassium (+1) and oxygen (-2). Since KMnO4 is a neutral compound, the sum of the oxidation numbers must equal zero. Thus, the oxidation number of Mn can be calculated by solving the equation: 2(+1) + x + 4(-2) = 0, where x represents the oxidation number of Mn. Solving for x gives Mn a +7 oxidation number.
The oxidation number of manganese in KMnO₄ is +7. Manganese has an oxidation number of +7 in this compound because oxygen has an oxidation number of -2, and the overall charge of the permanganate ion is -1, so the sum of the oxidation numbers must equal -1.
In KMnO4, the oxidation numbers are: K(+1), Mn(+7), and O(-2).
The maximum oxidation number is the highest possible oxidation state that an element can exhibit in a chemical compound. It is typically reached when the element gains or loses electrons to achieve a stable configuration.