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What is net ionic equation for sodium iodide and silver nitrate when precipitate is formed?
The net ionic equation for the reaction between sodium iodide (NaI) and silver nitrate (AgNO3) when a precipitate is formed is:
2Ag+ + 2I- -> Ag2I (s)
This equation represents the formation of silver iodide (AgI) precipitate when silver cations react with iodide anions.
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Silver nitrate and potassium iodide?
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
What happen when you add iodide to silver nitrate?
When iodide is added to silver nitrate, a chemical reaction occurs, resulting in the formation of silver iodide precipitate. This can be represented by the equation: AgNO3 + KI -> AgI(s) + KNO3. The silver iodide formed is insoluble in water and appears as a yellow precipitate.
Lead nitrate is treated with potassium iodide solution?
A yellow precipitate of lead(II) iodide is formed, according to the following balanced chemical equation: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3
What happens when iodide is mixed with silver nitrate?
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI → 2AgI + 2KNO3.
What happens when you mixed Lead Nitrate with Sodium Iodide?
When lead nitrate is mixed with sodium iodide, a solid precipitate of lead iodide is formed along with sodium nitrate. This reaction is a double displacement reaction where the cations of the two compounds switch partners to form the products. Lead iodide is a yellow precipitate that can be easily observed in the reaction mixture.
Silver nitrate and potassium iodide?
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
What happen when you add iodide to silver nitrate?
When iodide is added to silver nitrate, a chemical reaction occurs, resulting in the formation of silver iodide precipitate. This can be represented by the equation: AgNO3 + KI -> AgI(s) + KNO3. The silver iodide formed is insoluble in water and appears as a yellow precipitate.
Lead nitrate is treated with potassium iodide solution?
A yellow precipitate of lead(II) iodide is formed, according to the following balanced chemical equation: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3
What happens when iodide is mixed with silver nitrate?
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI → 2AgI + 2KNO3.
What happens when you mixed Lead Nitrate with Sodium Iodide?
When lead nitrate is mixed with sodium iodide, a solid precipitate of lead iodide is formed along with sodium nitrate. This reaction is a double displacement reaction where the cations of the two compounds switch partners to form the products. Lead iodide is a yellow precipitate that can be easily observed in the reaction mixture.
What is observed when a solution of potassium iodide is added to silver nitrate solution?
A yellow precipitate of silver iodide is formed due to the reaction between potassium iodide and silver nitrate, as silver iodide is insoluble. The reaction can be described by the equation: 2KI (aq) + AgNO3 (aq) → AgI (s) + 2KNO3 (aq)
Silver nitrate and strontium iodide?
When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.
What is the precipitate of lead nitrate and potassium iodide?
The precipitate formed when lead nitrate and potassium iodide are mixed is lead iodide. Lead iodide is a yellow solid that forms because of the insolubility of lead iodide in water.
What is the test for hydrogen iodide?
Hydrogen iodide can be tested using silver nitrate solution. When hydrogen iodide is bubbled through silver nitrate solution, a yellow precipitate of silver iodide is formed. This confirms the presence of iodide ions in the sample.
When potassium iodine solution is added to a solution of lead nitrate in a test tube what will be the compound precipitate?
The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.
What happens when you mix solutions of lead nitrate and potassium iodide?
When solutions of lead nitrate and potassium iodide are mixed, a yellow precipitate of lead iodide is formed. This reaction is a double displacement reaction where the lead from lead nitrate reacts with the iodide from potassium iodide to form the insoluble lead iodide.
What is the precipitate formed from Silver Nitrate and Lead Nitrate?
When Silver Nitrate and Lead Nitrate are combined, a yellow precipitate of Lead(II) iodide (PbI2) is formed due to the displacement reaction between silver and lead ions.
