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What is ammonium molybdate test?

Anonymous

∙ 12y ago

Updated: 5/31/2024

The ammonium molybdate test is a qualitative analytical test used to detect the presence of phosphate ions in a sample. It involves adding ammonium molybdate reagent to the sample, resulting in the formation of a yellow precipitate if phosphate ions are present. The intensity of the yellow color can provide an indication of the concentration of phosphate ions in the sample.

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Q: What is ammonium molybdate test?

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How do you make 0.1m of ammonium molybdate?

To make 0.1m of ammonium molybdate, you would need to dissolve the appropriate amount of ammonium molybdate powder in a specific volume of water to achieve a molarity of 0.1M. The molecular weight of ammonium molybdate is 196.00 g/mol, so for 0.1M solution, you would dissolve 19.6g of ammonium molybdate in water to make a final volume of 1 liter.

Why Ammonium molybdate is used in test for phosphorus?

Ammonium molybdate is used in the test for phosphorus because it forms a yellow complex with phosphorus, which allows for the colorimetric determination of phosphorus levels. This reaction is commonly used in spectrophotometric methods to quantify phosphorus in various samples.

Is ammonium molybdate a base?

No, ammonium molybdate is not a base. It is a chemical compound commonly used in analytical chemistry for the detection of phosphates and silicates.

What is molybdate test?

The molybdate test is a method used to detect the presence of orthophosphate in water or soil samples. It involves the addition of ammonium molybdate reagent to the sample, which forms a blue complex with orthophosphate ions. The intensity of the blue color is proportional to the concentration of orthophosphate in the sample.

How do you prepare 0.5M ammonium molybdate?

To prepare 0.5M ammonium molybdate solution, dissolve the appropriate amount of ammonium molybdate tetrahydrate in deionized water and dilute to the desired volume. The molar mass of ammonium molybdate tetrahydrate is 284.95 g/mol, so to make a 0.5M solution, you would need to dissolve 14.25 g of the compound in water and dilute to 1 liter.

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Related Questions

Would a hydrolysate of casein give a positive test with ammonium molybdate?

A hydrolysate of casein would likely not give a positive test with ammonium molybdate, as casein hydrolysate molecules are broken down into smaller peptides and amino acids, which may not have the specific chemical groups necessary for the molybdate test to detect. The test with ammonium molybdate typically reacts with phosphorus compounds to form a colored compound, and casein hydrolysate may not contain sufficient phosphorus for a positive result.

How do you make 0.1m of ammonium molybdate?

To make 0.1m of ammonium molybdate, you would need to dissolve the appropriate amount of ammonium molybdate powder in a specific volume of water to achieve a molarity of 0.1M. The molecular weight of ammonium molybdate is 196.00 g/mol, so for 0.1M solution, you would dissolve 19.6g of ammonium molybdate in water to make a final volume of 1 liter.

Why Ammonium molybdate is used in test for phosphorus?

Ammonium molybdate is used in the test for phosphorus because it forms a yellow complex with phosphorus, which allows for the colorimetric determination of phosphorus levels. This reaction is commonly used in spectrophotometric methods to quantify phosphorus in various samples.

Is ammonium molybdate a base?

No, ammonium molybdate is not a base. It is a chemical compound commonly used in analytical chemistry for the detection of phosphates and silicates.

What is molybdate test?

The molybdate test is a method used to detect the presence of orthophosphate in water or soil samples. It involves the addition of ammonium molybdate reagent to the sample, which forms a blue complex with orthophosphate ions. The intensity of the blue color is proportional to the concentration of orthophosphate in the sample.

What colour is the precipitate sodium phosphate and ammonium molybdate form?

The precipitate formed from sodium phosphate and ammonium molybdate is yellow.

How do you prepare ammonium molybdate?

Ammonium molybdate is (NH4)2MoO4. Its molar mass is 148g/mol. A 0.5M solution will have half a mole per liter of water. Half a mole of ammonium molybdate is 74g, so you would measure out 74g of it, and dissolve it in a liter of water.

How do you prepare 0.5M ammonium molybdate?

To prepare 0.5M ammonium molybdate solution, dissolve the appropriate amount of ammonium molybdate tetrahydrate in deionized water and dilute to the desired volume. The molar mass of ammonium molybdate tetrahydrate is 284.95 g/mol, so to make a 0.5M solution, you would need to dissolve 14.25 g of the compound in water and dilute to 1 liter.

Is ammonium molybdate an acid or base?

Methane can be protonated by superacids to the carbonium ion: H+ + CH4 -> [CH5]+ So methane is a Lewis base but, like helium, it is an exceedingly feeble proton abstractor. and They can lose a proton, but their tendency to lose a proton is so small that the term acid would not normally be applied to them.

Is ammonium molybdate a green chemical?

Ammonium molybdate is not considered a green chemical. It is a chemical compound that is commonly used as a catalyst, reagent, or analytical reagent. However, it has been classified as harmful to the environment and aquatic life, and therefore proper precautions should be taken when handling and disposing of it.

How would you test a urine sample for phosphate ions?

To test a urine sample for phosphate ions, you can use a phosphate test strip or a colorimetric method. The test strip changes color in the presence of phosphate ions, providing a semi-quantitative result. Alternatively, a colorimetric method involves adding reagents that react with phosphate ions to produce a colored solution whose intensity can be measured to quantify phosphate levels in the urine sample.

How do you test whether it is phosphoric acid or sulfuric?

Neutralize a few ml of phosphoric acid and add dilute nitric acid . Then add an equal volume of ammonium molybdate and warm. A bright canary-yellow precipitate is obtained which is soluble in dilute ammonia

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