0
HCl(g) stands for hydrogen chloride gas. It is a compound consisting of hydrogen and chlorine atoms, commonly known as hydrochloric acid in its liquid form. Hydrochloric acid is a strong acid that is widely used in industrial applications and chemical processes.
Add your answer:
Earn +20 pts
How many moles HCl in 8.3 g HCl?
There are 0.224 moles of HCl in 8.3 g of HCl. This is calculated by dividing the mass of HCl by its molar mass (36.46 g/mol).
How many moles of atoms are present in 154 g of HCl?
To find the number of moles of atoms in 154 g of HCl, we first need to calculate the molar mass of HCl. The molar mass of HCl is 1 g/mol (for hydrogen) + 35.5 g/mol (for chlorine), which equals 36.5 g/mol. Next, we divide the given mass by the molar mass to get the number of moles: 154 g / 36.5 g/mol = 4.22 moles. Therefore, there are approximately 4.22 moles of atoms in 154 g of HCl.
How do you convert 65.0 g HCl to moles?
To convert grams of a substance to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of HCl (hydrochloric acid) is 36.46 g/mol. Therefore, 65.0 g of HCl is equivalent to 65.0 g / 36.46 g/mol = 1.78 moles of HCl.
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
To find the mass of HCl needed to react completely with 0.20 g of ammonia gas, you need to use the stoichiometry of the balanced chemical equation of the reaction between HCl and ammonia. From the balanced equation, determine the mole ratio between HCl and ammonia. Then use this ratio to calculate the mass of HCl required to react completely with 0.20 g of ammonia gas.
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
To find the number of grams of HCl in 4.25 mL of a 0.405 M solution, first calculate the number of moles in 4.25 mL, which is 0.00171 moles. Then use the molar mass of HCl (36.46 g/mol) to find that 0.00171 moles is equal to 0.0623 grams of HCl.
How many moles HCl in 8.3 g HCl?
There are 0.224 moles of HCl in 8.3 g of HCl. This is calculated by dividing the mass of HCl by its molar mass (36.46 g/mol).
What is he necessary amount of chlorine needed to prepare 25.00 g of hydrogen chloride by reacting hydrogen with chlorine?
H2 (g) + Cl2 (g) --> 2 HCl (g) 25.00 g HCl x 1 mol HCl x 1 mol Cl2 x 70.90 g Cl2 = 24.3 g Cl2 are needed. ................... 36.46 g HCl . 2 mol HCl .. 1 mol Cl2
How many moles of atoms are present in 154 g of HCl?
To find the number of moles of atoms in 154 g of HCl, we first need to calculate the molar mass of HCl. The molar mass of HCl is 1 g/mol (for hydrogen) + 35.5 g/mol (for chlorine), which equals 36.5 g/mol. Next, we divide the given mass by the molar mass to get the number of moles: 154 g / 36.5 g/mol = 4.22 moles. Therefore, there are approximately 4.22 moles of atoms in 154 g of HCl.
if 6.5g of zn reacts with 5g of hcl?
7.3 g of HCl.
How do you convert 65.0 g HCl to moles?
To convert grams of a substance to moles, you need to divide the given mass by the molar mass of the substance. The molar mass of HCl (hydrochloric acid) is 36.46 g/mol. Therefore, 65.0 g of HCl is equivalent to 65.0 g / 36.46 g/mol = 1.78 moles of HCl.
How many grams of HCl must be dissolved in 275.0 g of water to prepare a 1.5 molal solution?
The answer is 15,039 g hydrogen chloride (HCl).
How many molecules are present in 0.340g of HCl?
0,34 g HCl contain 5,6.10e21 molecules.
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
To find the mass of HCl needed to react completely with 0.20 g of ammonia gas, you need to use the stoichiometry of the balanced chemical equation of the reaction between HCl and ammonia. From the balanced equation, determine the mole ratio between HCl and ammonia. Then use this ratio to calculate the mass of HCl required to react completely with 0.20 g of ammonia gas.
How many grams of HCl are contained in 4.25mL of a 0.405M aqueous solution of HCl?
To find the number of grams of HCl in 4.25 mL of a 0.405 M solution, first calculate the number of moles in 4.25 mL, which is 0.00171 moles. Then use the molar mass of HCl (36.46 g/mol) to find that 0.00171 moles is equal to 0.0623 grams of HCl.
What is the name for hcL AQ?
It is actually HCl(aq) Its chemical name is Hydrochloric acid
WHAT IS Keq for the reaction 2HCI(g) H2(g) plus CI2(g)?
The equilibrium constant, K_eq, for the reaction 2HCl (g) → H₂ (g) + Cl₂(g) is equal to [H₂][Cl₂]/[HCl]².
What is common name for HCl?
Hydrogen chloride is the common name for HCl
