To neutralize NaOH, which is a base, with HCl, which is an acid, we need to use an equal number of moles of each. Since the concentration of HCl is 3N, this means 3 moles of HCl are present in 1 liter. 20mL of a 3N solution of HCl would contain 0.06 moles, but that's already answered, so it would take 20mL of 3N HCl to neutralize 20mL of NaOH.
To make 500mL of 3N NaOH solution, you need to dissolve 15g of NaOH pellets in enough water to make 500mL of solution. Calculate the amount of NaOH needed by using the formula: (g = (N \times M \times V) / 1000), where (N = normality (3N)), (M = molar mass of NaOH (40 g/mol)), and (V = volume in liters (0.5 L)).
Heating NaOH before adding BaCl2 helps to dissolve NaOH completely in water, ensuring that no solid NaOH remains undissolved in the solution. This is important because the reaction between BaCl2 and NaOH requires the NaOH to be in solution to react with the BaCl2. Heating the solution can also speed up the reaction between NaOH and BaCl2.
The dissociation reaction of NaOH in water is as follows: NaOH (s) → Na+ (aq) + OH- (aq)
One Mole of Sodium Hydroxide NaOH= 40.00g/l =1N (8.0g NaOH in 100.0ml of water)= 2N NaOH or (80g of NaOH in 1L of water)= 2N NaOH
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
what is 3n times 3n-1
No. 3n is not a factor of 3n + 7.
No. 3n is not a factor of 3n + 7.
The GCF is 3n.
25-3n = 22
No. 3n isn't a factor of 3n + 7. The GCF of 3n + 7 and 9n is 1.
3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.
3n^4 divided by 3n^3 = n
3n+2+3n+2=6n+4