Yes, (NH4)2CO3 is soluble in water. When it dissolves in water, it dissociates into ammonium ions (NH4+) and carbonate ions (CO3^2-).
(NH4)2CO3 is an ionic compound. It is composed of ammonium ions (NH4+) and carbonate ions (CO3^2-), which are held together by electrostatic attractions between the positively and negatively charged ions.
The symbol equation for ethanoic acid (CH3COOH) reacting with ammonium carbonate [(NH4)2CO3] is: CH3COOH + (NH4)2CO3 -> CH3COONH4 + H2O + CO2
The chemical equation for the thermal decomposition of ammonium carbonate is: (NH4)2CO3 → 2NH3 + CO2 + H2O
The reaction between ammonia (NH3) and sodium carbonate (Na2CO3) results in the formation of ammonium carbonate [(NH4)2CO3]. This reaction can be represented by the chemical equation: 2NH3 + Na2CO3 → (NH4)2CO3 + 2NaOH.
The formula for ammonium carbonate is (NH4)2CO3.
The chemical formula for ammonium carbonate is (NH4)2CO3.
(nh4)2co3
(nh4)2co3
(NH4)2CO3
(nh4)2co3
There are 4.50 moles of NH4 2CO3 in 4.50 mol NH4 2CO3. Since each formula unit of NH4 2CO3 contains 2 moles of ammonium ions (NH4+), there would be 2 * 4.50 = 9.00 moles of ammonium ions in 4.50 mol NH4 2CO3.
ammonium carbonate
Ammonium carbonate is a solid.
The chemical formula for ammonium carbonate is (NH4)2CO3. It is composed of two ammonium ions (NH4+) and one carbonate ion (CO3^2-).
Yes, (NH4)2CO3 is soluble in water. When it dissolves in water, it dissociates into ammonium ions (NH4+) and carbonate ions (CO3^2-).
To find the number of moles of hydrogen in 3.5 moles of (NH4)2CO3, first identify the stoichiometry of the compound. In (NH4)2CO3, there are two moles of hydrogen per mole of compound. Therefore, in 3.5 moles of (NH4)2CO3, there would be 2 * 3.5 = 7 moles of hydrogen.