When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
When potassium iodide reacts with barium nitrate, a double displacement reaction occurs. The potassium ions and barium ions switch places to form potassium nitrate and barium iodide. Both products are insoluble and will form a precipitate.
The molecular equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is: AgNO3 + KI → AgI + KNO3. This reaction forms silver iodide (AgI) and potassium nitrate (KNO3).
The reaction between silver nitrate and potassium iodide forms silver iodide precipitate and potassium nitrate. This reaction is a double displacement reaction where the silver ions from silver nitrate switch places with the potassium ions in potassium iodide.
When potassium iodide and lead nitrate are mixed, a yellow precipitate of lead iodide forms in the solution, while potassium nitrate remains dissolved in the liquid.
Silver iodide (AgI), a precipitate insoluble in water, don't react with potassium nitrate.
When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.
The products are Mercury(II) iodide and Potassium nitrate
When potassium iodide reacts with barium nitrate, a double displacement reaction occurs. The potassium ions and barium ions switch places to form potassium nitrate and barium iodide. Both products are insoluble and will form a precipitate.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.
A white precipitate of silver iodide forms due to the reaction between silver ions and iodide ions, leaving potassium nitrate in solution. This reaction is a double displacement reaction and is used as a test for iodide ions.
The molecular equation for the reaction between silver nitrate (AgNO3) and potassium iodide (KI) is: AgNO3 + KI → AgI + KNO3. This reaction forms silver iodide (AgI) and potassium nitrate (KNO3).
The precipitate formed when lead nitrate and potassium iodide are mixed is lead iodide. Lead iodide is a yellow solid that forms because of the insolubility of lead iodide in water.
The reaction between silver nitrate and potassium iodide forms silver iodide precipitate and potassium nitrate. This reaction is a double displacement reaction where the silver ions from silver nitrate switch places with the potassium ions in potassium iodide.
When potassium iodide and lead nitrate are mixed, a yellow precipitate of lead iodide forms in the solution, while potassium nitrate remains dissolved in the liquid.
The symbol equation for silver nitrate solution and potassium iodide is: AgNO3(aq) + KI(aq) -> AgI(s) + KNO3(aq).
When silver nitrate and potassium iodide are combined, they undergo a double displacement reaction. Silver iodide is formed as a yellow precipitate, while potassium nitrate remains in solution. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3.